Homework Answers
| 20 to 30 | 31 to 40 | 41 to 50 | Over 50 | Total | ||
| Newspaper | Observed | 20 | 63 | 94 | 147 | 324 |
| Expected | 49.25 | 97.85 | 95.58 | 81.32 | 324.00 | |
| O - E | -29.25 | -34.85 | -1.58 | 65.68 | 0.00 | |
| (O - E)² / E | 17.37 | 12.41 | 0.03 | 53.04 | 82.85 | |
| Radio/TV | Observed | 28 | 126 | 165 | 89 | 408 |
| Expected | 62.02 | 123.22 | 120.36 | 102.41 | 408.00 | |
| O - E | -34.02 | 2.78 | 44.64 | -13.41 | 0.00 | |
| (O - E)² / E | 18.66 | 0.06 | 16.56 | 1.76 | 37.03 | |
| Internet | Observed | 104 | 113 | 36 | 15 | 268 |
| Expected | 40.74 | 80.94 | 79.06 | 67.27 | 268.00 | |
| O - E | 63.26 | 32.06 | -43.06 | -52.27 | 0.00 | |
| (O - E)² / E | 98.25 | 12.70 | 23.45 | 40.61 | 175.02 | |
| Total | Observed | 152 | 302 | 295 | 251 | 1000 |
| Expected | 152.00 | 302.00 | 295.00 | 251.00 | 1000.00 | |
| O - E | 0.00 | 0.00 | 0.00 | 0.00 | 0.00 | |
| (O - E)² / E | 134.28 | 25.18 | 40.04 | 95.41 | 294.90 | |
| 294.90 | chi-square | |||||
| 6 | df | |||||
| 1.01E-60 | p-value |
Answers:
Determine null and alternate hypothesis
Option C is correct
X^2= 294.90
P value=0.000
Reach a decision Option B is correct
Can the marketing? Option B is correct
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