We evaluate the value of the given integral by using given
value.
4. If \,f(x)dx = 10 and 1, g(x)dx = 6, then S,[2f(x) – 3g(x)]dx is 31
4. If si f(x)dx = 10 and si g(x)dx = 6, then [2f(x) – 39(x)]dx is
a. 8.2 Suppose that S* f(x) dx = 6, 5+ g(x) dx = 4, and Sf(x) dx = 2. Evaluate the following integrals: - Sa 2f(x) dx (2 Marks) S*(3f(x) - 29(x)) dx (2 Marks) S* f(x)g(x) dx (2 Marks) SIC) dx (2 Marks) C. d. g(x) Sub Total 20 Marksl
8.2 Suppose that ,* f(x) dx = 6, 8* g(x) dx = 4, and S f(x) dx = 2. Evaluate the following integrals: a. -S2f(x) dx (2 Marks) b. Si(3f(x) – 2g(x)) dx (2 Marks) c. $*f(x)g(x) dx (2 Marks) d. S@dx (2 Marks) [Sub Total 20 Marks]
If S® f(x) dx = 39 and fo* scu g(x) dx = 14, find • Bºca [2f(x) + 49(x)] dx.
Question 1 1 pts If f(x)dx = 10 and Să f(x) = 3.6, find si f(x)dx. 6.4 Question 2 1 pts Let Só f(x)dx = 6, Sº f(x)dx = -4, So g(x)dx = 12, S g(x)dx = 9 Use these values to evaluate the given definite integral: Si (35(x) + 2g(x))dx —
(1 point) Let [ f(z)dx=-13, 5° f(x) dx = 3, $*g(x) dx = 6, §*9(a) dx = 1, J2 Use these values to evaluate the given definite integrals. a) ["{$(2) + 9()) dx = 6 .) – g(x)) dx = * (31(2) + 29(2) de = (af(x) + g()) dc = 0. d) Find the value a such that a=
4. Given the integrals, [° 8(x) dx =-7, 5*8(x)dx = 6 and 5*g(x) dx = 10, use the properties of integrals to determine the value of the integrals below. a) [°(f(x)+g(x)\dx b) ſ 8(x)dx (4 pts cach) c) $39(x)dx a [ f(x)dx
Let S f(w)dt = 6, f(x)dx = -4, log(x)dt = 12, 9(x) dx = 9 Use these values to evaluate the given definite integral: -3 (f(x) f(x) + g(x)) dx
Please show al work
1. (6pts) Given ( f(z)dx = 31 and ( f(z)dx = -11, evaluate using properties of definite integrals: a) ['f(z)dx = b) [ f()dx = c) ["-2f(x)dx =
(1 point) i * f(x) dx = 3 and ' s(x) dx = 4, what is the value of [ f(xBC) da where D is the rectangle: 3 < x < 4, 3 sy s 7?