Question

10 kip 25 kip 5 kip-ft 1-5 kippt 1.5 kip/ft 7 kip-fts B Cam 8ft 8ft 8ft Tallow = 24 ksi Callow = 14.5ksi swe (bending & shear) 1. Select an appropriate I shape that will carry the Loodig. 2. Make Smax < S deflection LAC= 16ft 14co=8ft Sallow L 240 46). maximum both must hint be checked! Note: Your design must satisfy both strength and deflection requirements!

Assume Young's Modulus of 200 GPa or 29000 ksi.

Answer 1

given 25 kip so kip 5k ft l.skift JJ 7k-ft 4 D B 8ft 8 Ft 8ft + allow = auksi allowe 145ksi Smax < Sallow RA TRC = 1.5x24 test10 = 71 kip Emoso RAXR4 + 5-7-25116-1.5Y24x12 TRX8 = 0 QURA+ 8 Pc = 834 RA + Rc = T1 RA = 16.625 kib RE 54.375 kip 22 SED Jokaps 16.695 4,625 5 р A B *0.375 32-375

max shear force = 32.375 kips BMD gokft 5kft B A IRV - 128 kft may 1281-ft I section max mity max = rallow Ilyman may 2481000 Rox1000 X 12 X I may Zmax = Guin

select sisxso sst NA A= 14.7 in d = 1 sinch b=5.64 tfo- iss I = 486 m3 2x = 64. Bin? t = 1622 7.5 Zmax = 64 provided = 64.8 2p7 max hence ok may 128x1000x12 64.8 = 23.703 41000 Psi = 23.703ksi < radlice. hence ok (b) check for sheale 5. (max = VAY THb Ау may at win. =(620X544)/75-1629 + 6.5-622) (5) (75-622) 2. Z 38.22898 in

32.315X 38.22898 4864 55 = 4.63 K8i < 14.5 kpi knce of So barred on may (Sheax + bending), appropriate I section ý S 15850 (i) check for max. deflection. 3 Op = +5x16 45XA6 + 128/16 - Louane 25x162 16 EI 38 -S960 40 ET uo DC = -Safox ft 10483 xl.sygy 30 BE = fisu. 6678123 k-in 29000 X466 k-in 2 .264 inch

Sall 340 = 8812 suo fall = 4 inch (Smay 1264 e allowe hence ok. (SB) 15X16² +1284162 SSX163 48E (sx). 5X164 1384 A 166 IGET - 1285.33 -12BS. 33 X123 29000 X 486 - 1575 inch (max) 1575 inch Sall = 16112 .8 inch २५० Somax C Sale hence ok

finally I section is $ 15X50 am by bending & Safe is shear & deflection also