Question

A 11.2 L balloon is filled with H2(g) at 55.12 oC producing a pressure of 1.21 atm. Assuming that the balloon can expand or contract over a sufficient range of volume, what is its volume in L when the temperature is 126.7 oC and the pressure is 1,810 torr?

---please show 3 decimal points

Answer 1

Given

P ₁ = 1.21 atm , V ₁ = 11.2 L , T ₁ = 55.12 + 273 = 328.12 K

P ₂ =1810 torr = 2.382 atm , V ₂ = ? , T ₂ = 126.7 + 273 = 399.7 K

In given case, amount of Hydrogen gas remains constant.

Hence, we can write n ₁ = n ₂

When n ₁ = n ₂ We have equation ( P ₁ V ₁ / T ₁ ) = ( P ₂ V ₂ / T ₂ )

On rearranging above equation ,we get

V ₂ = V ₁ $\times$ ( P ₁ / P ₂ ) $\times$ ( T ₂ / T ₁ )

Substituting given values in above equation ,we get

V ₂ = 11.2 L $\times$ ( 1.21 atm / 2.382 atm ) $\times$ ( 399.7 K / 328.12 K )

V ₂ = 6.93047 L

ANSWER : 6.930 L