Question

For cascaded block in Block Diagram reduction process, the transfer function should be

		The difference of individual gain
		The division of individual gain
		The sum of individual gain
		The product of individual gain

Answer 1

Solution is 07 (3) whose system open loop goin → let is OIP C(S) & lip is R(S) R(S) 67,(5) C(s) then CCS) RIS) 01, () but Tof is Cls) RIS) CIS RIS) on, (S) is Transfer function for a single block system whose open-loop - 07 (5) is also cascade Now if another transfer function is with 67, (5), 7,5) R(S) Gg1s) c(s) here we wyte (CS) 2 RIS) 07,05). Ca (5)

Transfer function is always CIS) R(S) from equation ((S) 6,15). Ca (5) R(S) System is Transfer function of two cascade the product of indivisual gain. Aw. option D blocks cascade are the and n. are if there open loop gains the of ไr blocks is 47, ,012-- RIS) 67,(5) 117 () IGASY CIS) Transfer function ((s) R(S) G7,(5) (72 (5) . Go(s) Choco is always Cascode block Transfer function of a product of of indivisual gain.

some reduction Technique other example of block reduction (s) RIS) - + (ohhh ! CRS) ((s) G, (S) - Gg(s) R(S) 62 (5) + T RIS) 6,132 Х ((S) (s) Tof. 12 67, (s) + 02 (5) RCS)