find the solution set in interval notation -44 so +9 -44 b. <0 u2 + 9...
Solve the inequalities. Write the solution sets in interval notation if possible. a. so b. <0 r2 20 -*2 d. >0
9) __ Solve the inequality. Write the solution set in interval notation. 9) - 82 + 6x + 16<0 A) (-0,-8) U (2,0) B) (-0,0) (-2, 8) (8,00) D) (-0,-2)(8.)
Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set. - 5(3x-6) < - 30 Choose the correct answer below that is the solution set to the inequality. O A. {X/X> 4) or (4,00) OB. {X/X <4) or (-0,4) O C. {XIX > 4) or (4.00) OD. {X/X <-4} or (-0,-4) Choose the correct graph below that is the solution set to the inequality. OA OB -6 6 9 -9 -6 -3 0 3...
Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set. - 2(4x-5)<2 Choose the correct and per below that is the solution set to the inequality O A. {x[x> 1} or (1,00) OB. {x\x < 1) or (-0,1) O C. {x}x< - 1} or [-00,- 1] OD. {x[x> 1} or [1.00]
Question 6 Solve: (write solution set in interval notation) x-1 x-2 x-x-2 a) <1 b) > 0 X-5
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b)
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d)
The interval notation (-3, 1) described in set builder notation is {* | -3 5xs1} {x-3<x<1) {x-35x<1} {x|-3<x51} The set-builder notation {xl-55x<8} is equivalent to (-5,8) O(-5, 8] O [-5,8) O [-5, 8] To solve 2x - 11<3, one must consider only one case two different cases three different cases O four different cases If f(x) = 3x2 and g(x) = x + 2, then (gf)(x) is 3x2 + 2 3x3 + 6x2 03x2 + x...
3) Solve the following inequality. Express the solution using interval notation. 2x +1 <0 Answer
Solve the inequalities. Write the solution sets in interval notation if possible. 6 (a) <o y +1 6 (b) <0 y +1 (c) 20 y+1 (d) >0 y +1
Which among the following could be the member for set A = {X | X is the square of an integer and x < 100}? Select one: a. {1,4,5, 16, 20, 36, 64, 81, 85, 99} b. {0, 1, 4, 9, 16, 24, 36, 49, 68, 81} C. {0, 1,4,9, 16, 25, 36, 49, 64, 81} d.{1,4,9, 16, 25, 36, 64, 81, 99}
So 0<t<5 Using the Laplace transform, solve the initial value problem y' + y = 3 t5 y'(0) = 0. 9