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Acar company developed a certain car model to appeal to young consumers. The car company dames the storage age of drteers of
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a) The 95% confidence interval to estimate the average age of the car driver is given by,

CI=(\bar{x}\pm z_{\alpha /2}\times \frac{\sigma }{\sqrt{n}})

where, \bar{x}=29.90, \sigma =2.5, n=18

1-\alpha =0.95\Rightarrow \alpha =0.05\Rightarrow \alpha /2=0.025

We will get the value of -a/2 from the last row of t-table.

From t-table,  20/2 = 20.025 = 1.96

So, the 95% confidence interval is given by,

CI=(29.90\pm 1.96\times \frac{2.5}{\sqrt{18}})

=(29.90\pm 1.96\times 0.5893)

=(29.90\pm 1.155)

=(28.745,31.055)

The 95% confidence interval for the average age of the car driver has a lower limit of 28.75 years old and an upper limit of 31.06 years old.

b) Does the result lend support to the car company's claim?

A) No, because the interval does not include the company's claimed average data.

c) What assumption needs to be made to construct this interval?

A) The population of the model's drivers' ages is normally distributed.

Please upvote my answer if you find it helpful. Thanking you.

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