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Acar company developed a certain car model to appeal to young consumers. The car company claims the average age of dris age o
or company claims the average age of drivers of this certain car model is 27.00 years old. Suppose a random sample of 17 driv
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Answer #1

Given :

Given that,

Sample mean = \bar x = 29.10

Standard deviation = s = 2.8

Sample size = n = 17

Degrees of freedom = df = n - 1 = 17 - 1 = 16

At 95% confidence level, critical value of t is ,

\alpha = 1 - 95% = 1 - 0.95 = 0.05

\alpha / 2 = 0.05 / 2 = 0.025

t\alpha /2,df = t0.025,16 = 2.120

Margin of error = E = t\alpha/2,df * (s /\sqrtn)

= 2.120 × (2.8 / √17)

= 1.4397

The 95% confidence interval estimate of the population mean is,

CI = \bar x - E < \mu < \bar x + E

= 29.10 - 1.4397 < \mu < 29.10 + 1.4397

27.66 < \mu < 30.54

The 95% confidence interval for the average age of the car driver has a lower limit of 27.66 years old and an upper limit of 30.54 years old.

b) No, because the interval does not includes the company's claimed average age.

c) The population of all car drivers' ages is normally distributed.

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