Question

As part of a research program for a new cholesterol drug, a pharmaceutical company would like to investigate the relationship between the ages and LDL low-density lipoprotein cholesterol of man. The accompanying data set shows the ages and LDL cholesterol levels of seven randomly selected man. You meet a 38-year-old man and want to guess LDL cholesterol level. What interval would you use so that you we 95% confident that the LDL cholesterol level of this person will Chak the icon to view the datatable Olemmine the user and lower limits of this interval Upper Lim. LowLm - (Round to one decimal place as needed)

Answer 1

SX 232 2 {(x-x, 1184 = 169.143 - n. = 4030.857 from data 33.143 X - mean age - Ssx=366.857 Ý = Ey 7 ECY_%) 2 = SSY {(x-7)(y-7) = 574.857 57 4.857 1.56697841 {(x-x)2 366.857 Boa T-B, F = 169.143 - 156697841 *3 3.143 Po = 117.208635 Regression egn is } = Bo + 8 x ß, = {(x-7)(y-Y) = 117.208635+ 1.5669784 1 X

SsTotal ssy = 4090.8 57 ssreg B, Ssxy = 1.5669784 18574.857 - 900.78 8508 SSE SS Total SsReg = 3130.068 49 SSE 3130.06849 626,013 698 n-2 R 25.0202657 tala x = 36 117.208635 +1.5669784 1836 ŷ = 173, 619858 confidence interval is ŷ } talar ħ + (xo-*)? {(X-X) 2 x=0.05 4/2 = 0.025 nl = 2.4469 ŷ = 173.619858 Xo = 36 CI is 173.6198587 2:4469 X 25,0 202657 + (36-33.143)2 366.857 173.6198587 61.2220881 173.619858761.222088110.165106818 173.6198 58 † 61.22 20881 X0.406333383 173.619858724.8765782 148.74328 , 198.496436) (148.7, 198,5) a is confidence in which cholesterol level of 36 year old person fall. 10.122854 0.0222496749 interval