Question

The 12.3-ft steel beam is being hoisted from its horizontal position by the two cables attached at A and B. If the initial angular accelerations are 01 = 0.51 rad/sec2 and 02 = 0.76 rad/sec, determine the initial values of (a) the angular acceleration a positive if counterclockwise, negative if clockwise) of the beam, (b) the acceleration of point C (positive if up, negative if down), and (c) the distance d (positive if to the right, negative if to the left) from A to the point on the centerline of the beam which has zero acceleration. 12" 12" 01 02 4.1 4.1 4.1 UB C Answers: (a) a = rad/sec2 (b) ac = ft/sec (c) d = lft

Answer 1

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Som - Given 2 - o'st sadisec final Answer (a) a= -0.061 rad/ 02=0.76 rad/sec? (b) Ac = +0.375 f 15 (6) X-71.646 bet 12" as regad K-4.1_sk 4:1't >k 4:1-> A B K > 4. i central line) Since angular acces of first pulley = di = 0.51 radls2 actor of point ponithe string = Quiri) = 0-5186) 9 ap= 3.06 inch/sec² TIR & Accs of point a' on the string = {282) pt o on beam 0.76 X6 (lupwards of Let o be the centre pt of Beam Tag = 4.56 inch/se? :: accln of poiny 'o' = 102-apon [ Angular accio of Libeem = 1 4:56- 3.061 (4:12X12 la Angular aceloof-be.com 0.732 rad|sec( anticlockwise duer"] 12 0.061 radi? 12 [b] Ace of point 'c' = (& beam X Oc) = 0.732 x (40°1740 2 4.502 fy - 0.375 His? ( upward) (d] Let a be the desternce from 'Al shere accino 08 (4.18x) = tre) 3.06 4.56 (4.1-2) >x=10646 bt e as right fa

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