Question

The metal plate shown is held in position by a pin connection at B and a roller at C. Find the reactions at B and C for the equilibrium of the plate. F1=3500lb Write the final answer here and upload the file with step by step calculations. F1 26° А с 10 ft 9 ft 2 ft B

Answer 1

Solution Fi A Lot F, = 3500 lb с loft oft K2F+ 1 B In Question there is no mention about maks of plate no conedering plate is massless metal plate FBD of metal plate - F, sim26 Rc Fi ch A here Re k reaction at RBx and RBy are reactions 269 ft Ficas 26" ܘܐ gft aft at B : B Rox EFHE RBY Equilibrium condition - Sum of all forces in hauzontal deaction ( covej Rox - Ficos26 Rex = Ficos26 3500 C0826 Rege = 3145.78 lbi

Sum of all forces in vertical direction = 0 {fu (THve) Fixin26 R By - Rc=0 RBy + Rc = 3500 in 26 Roy + Rc = 153 4.3 eb eq -> Moment about any point EMB counter clock whe ove imter clock wue ove (ECO326)*9 - (Fix1m26)x 2 - Rc xp = 0 Rcx8 (3.500 cox 26hes (3500) X1126)2 Rc = 3155 · 43 lb putting value of Re im eq © Rby 1534.3 - 3155.43 R By - 1621.13 lb R. By comes with Ove sign it means direction of Roy is opposite from which we assume before. reaction direction is upward hot downward Rby as we arrume before at the start.

So final F.B.D. Rc = 3155.43 lb Fi Reactions at 'C' RBy=1621 - 13 eb Rc=3155.43 lb Roxa = 3145•78 lb Reactions at B In horizontal direction RB x = 31 45.78 llo In vertical direction Roy Roy = 1621-13 eb -- Answer