34. The NaOH concentration used in industrial grade is normally 3 to 6 M, and the...

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Answer 1

Answer #1

Solution: balanced reaction for sulphuric acid and sodium hydroxide is

H ₂SO₄ + 2 NaOH ----->>> Na ₂SO₄ + 2H ₂O

1 mol of sulfuric acid is required to neutralise 2 mol of NaOH

Number of moles = Volume of Solution × concentration

Number of moles of sulfuric acid = 0.5 M × 45.7 ml = 22.85 m mol

Number of moles of NaOH = 2 × 22.85 m mol = 45.7 m mol

Concentration of NaOH = mole of NaOH ÷ volume of NaOH = 45.7 m mol ÷ 20 mL = 2.28 M

Concentration of NaOH found is 2.28 M

Option (B) is correct 2.28 M

Answer 2

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