Question

do the part on red please.

1. Validate conclusions regarding the behavior of inductors in transient and steady-state DC network. 2. Verify basic equations for determining the total induction in series, parallel and series-parallel circuits. 3. Use simulation software to understand circuit characteristics. EQUIPMENT REQUIRED: Multisim tool. PROCEDURES: Part 1. Series RL Circuits Use the circuit of Figure 4 (pick RL=202). a. Calculate the steady-state values of IL and VL. IL = 20.4 mA VL = _0.408_V IL=10 / (470 + 20) = 0.0204 A = 20.4 mA and VL = voltage across 20 ohms =0.0204* 20 = 0.408 V b. Using Multisim for Figure 4, measure IL and VL. Compare the results with Part 1a above. IL 20.408m=ma VL =__408.16mV or 0.40816 V

Answer 1

ܠܢ a : R=200 IOV 2,- 10mH Ri 0 Solutions : This is Series RL circuit in which 4708 current i is geren be- i= V (1-78**) A R. Lobot here, Volov, RO 470+20 = 4902 Lo lomH G490 (1-400x 10X10 490 멋 - 49000$ = 0.0204(1-e JA In steady State (le after long time), exponential teron from a So, is lo 1 . O abore expressions become e = p į= 0.0204 A - 20-4 MA Before steady state, current will be little less that, 2014 mA because of exponential guese.

2 . 994. Capsfocose full "Change) BL - 2 ng 5 = 그 3. It takes 5 fione constant to charge indeector Hore time constant 10x103 R 490 * I 5 2.04 X10 So, fire time constant = 5 x 2.04x 10 -5 10X10 0-1 ms Al, f20- Inducta behares as ofen circuit So, Il = 0 Sence R is in 8 series with L So, locat across Jerellence will also also be o (at too). V = lov ( All voltage acrolls óodector; because there is oro-doo any of resistors.) We can found it by our expression also i = 2 0.0204 (1-e at to, is -0.020411-2°) - -ot IR 20 2 across 49000€) A *

=L(o-xxx-B) Bit Vė Rit) all V = Lidi (v dt de R R e & = xxy ek t at, $20, v=vell -Rexo Vari Y = lov a v so, at t=0, 12 4 . AH Reak R=2018 = un 1x103 10 Vi I, - R So, I =10mA REIK + > Li=10mH eller Slov

& = 020 Ime Tox jo3 A I2 = 8 ci e se py lo 1020 Ho20001 I= 9.8X003 (1- In = 9.8(1-ěl02000€)ma > at tro ( Steady State) In = 9.8(1-0) (1-0) = 9.8MA va at tzo, Il = I2 = 9.8(1-1) PLE onu, O = o V = ve so, vilattoo -10V tzo be constant le toma وه IRI will always