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Determine il(t) for in the circuit of Fig. P12.21 for t=16 ms, given that the switch...
Determine iL(t) for in the circuit of Fig. P12.21 for t =45 ms , given that...
Determine iL(t) for in the circuit of Fig. P12.21 for t =45 ms ,
given that the switch was opened at t = 0 after it had been closed
for a long time, vs = 12 mV, R0 = 5 Ω , R1 = 10 Ω,R2 = 20 Ω, L =
0.2 H, and C = 6 mF. Give the current in micro Amperes, Hint, the
initial conditions are zero and the steady state current in the
inductor will be...
I got the answer wrong but the correct answer is 348.7539 Use the Diagrams document. Determine...
I got the answer wrong but the correct answer is 348.7539
Use the Diagrams document. Determine il(t) for in the circuit of Fig. P12.21 fort =13 ms, given that the switch was opened at t = 0 after it had been closed for a long time, vs = 12 mV, RO = 50, R1 = 102, R2 = 2012, L = 0.2 H, and C = 6 mF. Give the current in micro Amperes, Hint, the initial conditions are zero...
1.29 The voltage source of the circuit shown in Fig. P1.29 is given by vs(t) =...
1.29 The voltage source of the circuit shown in Fig. P1.29 is given by vs(t) = 25 cos(4 x 104t - 45°) (V). Obtain an expression for il(t), the current flowing through the inductor IR vs() R23 R1 = 20 12, R2 = 30 12, L = 0.4 mH
Just before the switch is opened at t-0 in the given figure, the current through the...
Just before the switch is opened at t-0 in the given figure, the current through the inductor is i e 1.5 mA. Determine the voltage v3 across R3 immediately after the switch is opened, where Vs 12 V, R1-6 kohm, R2 = 6 kohm, R3 10 kohm, and L-0.9 mH. t-0 R2 IL The voltage vs across R3 immediately after the switch is opened is answer to one decimal place.) V. (Round the final
(3) The RL circuit shown in Figure 3 has a switch that is closed att 0....
(3) The RL circuit shown in Figure 3 has a switch that is closed att 0. Assume that the circuit has reached steady state prior to the switch closing. You are given R1 1 kQ, R2-10 kQ, R3-R4-100 k2, L 10 mH, Vs-5 V. (a) [15 pts] Calculate the steady-state inductor current before the switch is closed (b) [16 pts] Give the differential equation as an expression of the inductor current fort>0 (i.e. write the differential equation) (c) 13 pts]...
= 0 Rs=50 In the adjoining circuit, the switch, which had been closed for a sufficiently...
= 0 Rs=50 In the adjoining circuit, the switch, which had been closed for a sufficiently long time for steady state to be reached, is opened at time t = 0. Determine the following, as a function of time: (a) The current iz(t) through the inductor, and (6) The voltage vr(t) across the 1k12 resistor. Vs= 20 V ficco Ro 1 knull 1 H elle
In the adjoining circuit, the switch, which had been closed for a sufficiently long time for...
In the adjoining circuit, the switch, which had been closed for
a sufficiently long time for steady state to be reached, is opened
at time t = 0. Determine the following, as a function of time:
(a) The current I L(t) through the inductor, and (b) The voltage
v R(t) across the 1k Ohm resistor.
I=0 Rs=5.12 [26) Vs= + Ro= 1 k 2 20 V 1 H 0000 vr(t)
Problem 4 In the circuit shown below, the switch has been opened for a very long...
Problem 4 In the circuit shown below, the switch has been opened for a very long time prior to t= 0 and closes at t = 0 and remains closed for a long time. Please find: a) i (0), vc(ot), b) the steady-state voltage across the capacitor in terms of Us, Rı, and R2 c) the steady state current through the inductor in terms of Us, Ry, and R2 d) Write the differential equation for it) in terms of Vs,...
a)Find the voltage across inductor L1 at t=0^+ (i.e. just after the switch is opened) b)Determine...
a)Find the voltage across inductor L1 at t=0^+ (i.e.
just after the switch is opened)
b)Determine the voltage across L1 at time = 5us.
Problem 11: RL Discharging #2 Determine the voltages of a Resistor- Inductor circuit. Switch S1 has been closed for a long time and the Inductor L1 is completely charged. At time t -0s, Switch S1 is opened. R1 S1 R3 R2 L1 Given Variables Name Value Units E1 14 R1 15 kohm R2 kohm R3 17...
A common demonstration of inductance employs a circuit such as the one shown in the figure...
A common demonstration of inductance employs a circuit such as
the one shown in the figure (Figure 1) . Switch S is closed, and
the light bulb (represented by resistance R1) just barely glows.
After a period of time, switch S is opened, and the bulb lights up
brightly for a short period of time. To understand this effect,
think of an inductor as a device that imparts an "inertia" to the
current, preventing a discontinuous change in the current...
Determine iL(t) for in the circuit of Fig. P12.21 for t =45 ms ,
given that the switch was opened at t = 0 after it had been closed
for a long time, vs = 12 mV, R0 = 5 Ω , R1 = 10 Ω,R2 = 20 Ω, L =
0.2 H, and C = 6 mF. Give the current in micro Amperes, Hint, the
initial conditions are zero and the steady state current in the
inductor will be...
I got the answer wrong but the correct answer is 348.7539
Use the Diagrams document. Determine il(t) for in the circuit of Fig. P12.21 fort =13 ms, given that the switch was opened at t = 0 after it had been closed for a long time, vs = 12 mV, RO = 50, R1 = 102, R2 = 2012, L = 0.2 H, and C = 6 mF. Give the current in micro Amperes, Hint, the initial conditions are zero...
1.29 The voltage source of the circuit shown in Fig. P1.29 is given by vs(t) = 25 cos(4 x 104t - 45°) (V). Obtain an expression for il(t), the current flowing through the inductor IR vs() R23 R1 = 20 12, R2 = 30 12, L = 0.4 mH
Just before the switch is opened at t-0 in the given figure, the current through the inductor is i e 1.5 mA. Determine the voltage v3 across R3 immediately after the switch is opened, where Vs 12 V, R1-6 kohm, R2 = 6 kohm, R3 10 kohm, and L-0.9 mH. t-0 R2 IL The voltage vs across R3 immediately after the switch is opened is answer to one decimal place.) V. (Round the final
(3) The RL circuit shown in Figure 3 has a switch that is closed att 0. Assume that the circuit has reached steady state prior to the switch closing. You are given R1 1 kQ, R2-10 kQ, R3-R4-100 k2, L 10 mH, Vs-5 V. (a) [15 pts] Calculate the steady-state inductor current before the switch is closed (b) [16 pts] Give the differential equation as an expression of the inductor current fort>0 (i.e. write the differential equation) (c) 13 pts]...
= 0 Rs=50 In the adjoining circuit, the switch, which had been closed for a sufficiently long time for steady state to be reached, is opened at time t = 0. Determine the following, as a function of time: (a) The current iz(t) through the inductor, and (6) The voltage vr(t) across the 1k12 resistor. Vs= 20 V ficco Ro 1 knull 1 H elle
In the adjoining circuit, the switch, which had been closed for
a sufficiently long time for steady state to be reached, is opened
at time t = 0. Determine the following, as a function of time:
(a) The current I L(t) through the inductor, and (b) The voltage
v R(t) across the 1k Ohm resistor.
I=0 Rs=5.12 [26) Vs= + Ro= 1 k 2 20 V 1 H 0000 vr(t)
Problem 4 In the circuit shown below, the switch has been opened for a very long time prior to t= 0 and closes at t = 0 and remains closed for a long time. Please find: a) i (0), vc(ot), b) the steady-state voltage across the capacitor in terms of Us, Rı, and R2 c) the steady state current through the inductor in terms of Us, Ry, and R2 d) Write the differential equation for it) in terms of Vs,...
a)Find the voltage across inductor L1 at t=0^+ (i.e.
just after the switch is opened)
b)Determine the voltage across L1 at time = 5us.
Problem 11: RL Discharging #2 Determine the voltages of a Resistor- Inductor circuit. Switch S1 has been closed for a long time and the Inductor L1 is completely charged. At time t -0s, Switch S1 is opened. R1 S1 R3 R2 L1 Given Variables Name Value Units E1 14 R1 15 kohm R2 kohm R3 17...
A common demonstration of inductance employs a circuit such as
the one shown in the figure (Figure 1) . Switch S is closed, and
the light bulb (represented by resistance R1) just barely glows.
After a period of time, switch S is opened, and the bulb lights up
brightly for a short period of time. To understand this effect,
think of an inductor as a device that imparts an "inertia" to the
current, preventing a discontinuous change in the current...
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