hort Summary: The transient behavior of capacitor and inductor is important here. There can not be instantaneous change in voltage of current due to charge conservation rules and similarly in inductor current can't change instantaneously. Steady state behavior is defined here with time (t) tends to infinity.
Problem 4 In the circuit shown below, the switch has been opened for a very long...
do not use s domain method ,use only differential equation 3. In the circuit shown, switch 1 has been closed for a long time before it is opened at t 0, and switch 2 has been opened for a long time before it is closed at t = 0. SW2 sw, 0.5Ω R2 1(2 A, 20 A i(t) 0.5 H a. Find the initial voltage v(O)- Vo across the capacitor and initial current through the inductor (0) lo at t...
Problem 2 You are given the circuit shown below and you are told that the switch was closed for a long time prior tot0. Att0 the switchopens. IH 402 a) Find vc(0), i(0) dt c) Find the steady-state voltage Vess across the capacitor. d) Write the differential equation in terms of vc() indicated above. c) Is the transient response over, under or critically damped? Find v(t)t>0
7. Given the circuit below. The switch has been opened for a very long time. At t = 0, we close the switch. M 2007 M 100 av ile & 5mH a. What will be the initial current of the inductor at I.(t = 0)? (before switch is closed)? Why? b. What will be the final current of the inductor 1, (t +00)? (after switch has been closed for a long time) Why? C. Find the first order linear differential...
(3) The RL circuit shown in Figure 3 has a switch that is closed att 0. Assume that the circuit has reached steady state prior to the switch closing. You are given R1 1 kQ, R2-10 kQ, R3-R4-100 k2, L 10 mH, Vs-5 V. (a) [15 pts] Calculate the steady-state inductor current before the switch is closed (b) [16 pts] Give the differential equation as an expression of the inductor current fort>0 (i.e. write the differential equation) (c) 13 pts]...
The switch in the circuit shown below has been closed for a long time until t=0 when it is opened. What is the circuit time constant for t> 0? It=0 RS SR2 = 3R OT=[(R3 + RA)//R2 + R1]//R,C OT=R.C OT=RiC OT=R2C None of the above
Q3. In the circuit shown below, switch S has been closed for a very long time and it is opened at t = 0. Find the solution for the current i(t) passing through the inductor. Q4. In the circuit shown, the initial capacitor voltage is v(0) =5 V. (a) Find the capacitor voltage v(r) for t > 0. (b) Find the current io(t).
- Switch S Switch S2 42 х. 42 t 0 t-0 100u(t 1F + 4H 20) 40) LOOP 2 LOOP1 Figure 1 0. Before switch St closes, no energy is Switch S2 stays open while switch St closes at t stored in the inductor or capacitor. Namely-i (0- ) = uc ( 0) = 0. (a.) (10 points) Find i(t) when switch S, closes but switch S2 stays open. (b.) (10 points) After a long time or after an appropriate...
In the adjoining circuit, the switch, which had been closed for a sufficiently long time for steady state to be reached, is opened at time t = 0. Determine the following, as a function of time: (a) The current I L(t) through the inductor, and (b) The voltage v R(t) across the 1k Ohm resistor. I=0 Rs=5.12 [26) Vs= + Ro= 1 k 2 20 V 1 H 0000 vr(t)
a.) Consider the circuit below. Assume that the capacitor is fully discharged prior to t=0. The switch is closed at t=0 connecting the voltage source to the rest of the circuit. What is the steady-state value of the voltage across the capacitor, VC(t), after the switch is closed for a long time? Put your answer in the box below, without the units (Volts). b.) What is the time constant, ?, in ?s of the circuit in this question. c.) What...
The switch in the circuit below has been closed for a very long time. 2. a. What is the voltage across the capacitor? b. If the switch is opened, what is the time constant for discharging the capacitor? c. how long does it take the capacitor to discharge to 1/10th of its initial voltage? R1 = 1.00 Ω R2 = 8.00 Ω R3 = 4.00 Ω R4 = 2.00 Ω C = 1.00 μF Battery = 10.0 V R2 R4