Q5) In the circuit below the switch S, has been in open position for t < 0 for a long time, but it closes at t = 0. Find the capacitor voltage (Vc) for t <0 and t > 0. C1 Vs +L S1 R2 V = 10 V 1s = 1 A R= 20 R = 40 R1 w CSF
2 First-Order RC Circuit: Natural Response The switch in the circuit in Figure 2 has been in position for a long time. At t = 0, the switch moves to position (the switch opens) and stays there. Assuming that V. > O for the constant voltage source, (a) find vc(0-), vc(0+), ic(0-), and ic(0+); (b) find vc(t) when t 20 (if you want, you can write vo(t) by circuit inspection; you don't need to show the differential equation); and (c)...
For the following circuit the switch is open for t<0. At t=0 the switch is closed. . Assume Is=3.9 A. Find the equation iL(t)=k1+k2exp(−t/τ)for t>0 given Is=3.9 A. 20Ω 6H Switch closes at t-0 10Ω 10Ω 10() у.st. out
Solving for The switch in the circuit below has been closed for a long time and it opens at t = 0. Find the following: for b) can you solve it without using Laplace transform? As in no s domain, thank you 1. The switch in the circuit below has been closed for a long time and it opens at t = 0. Find the following: (a) (20 points) v(0%), and v.(0%) for t < 0. (b) (20 points) v(t),...
Problem 2 (35 points) In the circuit shown below, the switch is closed at t = 0. t=0 L = 1 mH C1 = 5 uF C2 = 10 uf = l(s) Problem 2 The capacitor voltages at t = 0 are VC, (0) VC, (0) = = -50 V 30 V where the capacitor voltage polarities are indicated on the circuit drawing. Solve for the loop current i(t) using the Laplace transform method.
9. For the given circuit, if the initial voltage across the capacitor is vc(0*) = 0, find an expression for the voltrage across the capacitor as a function of time and graph voltage versus time. R= 100 k2 w v=100 V uc) C = 0.01 uF 10. If a 100-F capacitance is initially charged to 1000V and at t=0, it is connected to a 1-ka resistance, at what time has 50 percent of the initial energy stored in the capacitance...
For the circuit shown in the figure, the switch S is initially open and the capacitor is uncharged. The switch is then dosed at time t = 0. How many seconds after closing the switch will the energy stored in live capacitor be equal to 50.2 mJ?
Part A The action of the two switches in the circuit seen in the figure is as follows. For t<0, switch 1 is in position a and switch 2 is open. This state has existed for a long time. At t 0, switch 1 moves instantaneously from position a to position b, while switch 2 remains open. Ten milliseconds after switch 1 operates, switch 2 closes, remains closed for 10 ms and then opens. (Figure 1) Find vo(t) 44 ms...
Values of v()/V = -1/ IR + (1)/V V R T 21 31 0.36788 0.13534 0.04979 0.01832 0.00674 ST Figure 1: A source free RC circuit. Table 1: values of the exponential term for different t Observe from the table 1 that the smaller the time constant, the more rapidly the voltage decreases, that is, the faster the response. This is illustrated in Fig. 2. A circuit with a small time constant gives a fast response in that it reaches...
pls answer 7&8 10 ks2 10 kg vo Problem 7) The switch in the circuit has been open for a long time. Find the time constant and the voltage on the capacitor as t oo and sketch the voltage vc(t) on the capacitor for t > 0. 10v 1 mA 20 k223 40 uF - Velt t = 012 2012 We Problem 8) The switch in the circuit has been closed for a long time before it opens at t...