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Question 9 (5 points) The generic reaction below has Kp = 25 when the temperature is 225°C: c(g) = D(9) If the initial partia

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Qur Cg Z Dego initial Satm at Equilibechu (5-X) Kp=25 o e kp = x PD Р.. (5-2) x 25 - (5-x) 125 25x=0 26X = 125 X=126 26 4.80

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