A. Calculate A Gº and Kp for the following equilibrium reaction at 25°C. The AG, values...
HELP PLEASE (a) Calculate AGⓇ for the following reaction at 298 K. The AGP values are 0 kJ/mol for Cl2(e) -325 kJ/mol for PC (e), and -286 kJ/mol for PC13(e). PCIE) - PC3(g) + Cl2(8) (6) Calculate AG at 298 K for the reaction if the partial pressures are PC12 -0.40 atm, PPC13 - 0.27 atm, and PPCIS -0.0029 atm.
() Calculate AGⓇ for the following reaction at 298 K. The AGP values are 0 kJ/mol for C12(e) -325 kJ/mol for Cisce), and -286 kJ/mol for PC13(e). PC1518) PC3(8) + Cl2(g) (b) Calculate AG at 298 K for the reaction if the partial pressures are PC120,40 atm, PPC13 -0.27 atm, and PPCi5 -0.0029 atm.
The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the reaction 24.64 kJ/mol Calculate AG for the reaction when the partial pressures are PH, 0.28 atm, Pco,0.75 atm, H2O = 0.65 atm, and CO*. Pco-1.16 atm. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the reaction 24.64 kJ/mol Calculate AG for the reaction when the partial pressures are PH, 0.28 atm, Pco,0.75 atm,...
The squares in the equation are equilibrium signs. The equilibrium constant, Ky, for the following reaction is 0.110 at 298 K: NH_HS(s) NH3(g) + H2S(g) Calculate the equilibrium partial pressure of H2S when 0.416 moles of NH_HS(s) is introduced into a 1.00 L vessel at 298 K. Phys= c atm The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PC15(g) PC13(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PC15(g) is introduced into...
03(g) + OH(g) =H(g) + 2 O2(g) AG° = 5.8 kJ/mol at 298 K, A,Gº = 0 kJ/mol at 354 K, and 4 Gº = -2.0 kJ/mol at 373 K. (a) Calculate the equilibrium constant value for this reaction at 298K, 354 K, and 373 K. (b) At 354K, calculate the change in the Gibbs energy of the reaction, AG when the partial pressures of O3 and OH are kept at 10 bar and 30 bar, respectively, while O2 and...
Practice Exercise 1 At 500 K, the reaction 2 NO(8) + Cl2(8) = 2 NOCI(8) has K, = 51. In an equilibrium mixture at 500 K, the partial pres- sure of NO is 0.125 atm and Cl, is 0.165 atm. What is the par- tial pressure of NOCI in the equilibrium mixture? (a) 0.13 atm (b) 0.36 atm (c) 1.0 atm (d) 5.1 x 10-5 atm (e) 0.125 atm Practice Exercise 2 At 500 K, the reaction PC15(8) = PC13(8) + Cl2(8) has...
The equilibrium constant Kp for the reaction PCl5(g) <---> PCl3(g) + Cl2(g) is 1.15 at 25 degrees Celsius. The reaction starts with a mixture of 0.177 atm PCl5, 0.223 atm PCl3, and 0.111 atm Cl2. When this mixture comes to equilibrium at 25 degrees Celsius, what are the equilibrium pressures of each component?
given: 2NO(g)+Cl2(g)⇌2NOCl(g) Kp=0.27 at 700 K A reaction mixture initially contains equal partial pressures of NO and Cl2. At equilibrium, the partial pressure of NOCl was measured to be 115 torr. What were the initial partial pressures of NO and Cl2?
Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) + CO(g) Calculate Δ G o for the reaction. kJ/mol Calculate Δ G for the reaction when the partial pressures are PH2 = 0.22 atm, PCO2 = 0.83 atm, PH2O = 0.66 atm, and PCO = 1.12 atm.
1. The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <----> PCl3(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PCl5(g) is introduced into an evacuated flask at a pressure of 1.00 atm at 500 K. PPCl5 = atm PPCl3 = atm PCl2 = atm 2. The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K: NH4I(s) <----> NH3(g) + HI(g) Calculate the equilibrium partial pressure of HI when...