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Question 32 (8 points) What mass of NH3 is formed when 9.32 g of Mg3N2 reacts with water according the equation? Mg3N2 + 6H20
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Answer #1

101g/mol of Mg3N2 formed = 17g/mol of NH3

So;

9.32g of Mg3N2 formed = (9.32 • 17)/(101) = 1.6g of NH3

Hence Answer is

Mass of NH3 = 1.6g (Answer)

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