Given that
= 71.50 / 1000 KJ/mol.K = 0.0715 KJ/mol.K
Boiling point can be calculated by the following formula,
For vaporisation
T = (14.50 KJ ) / ( 0.0715 KJ/mol.K) = 202.8 K
Hence the boiling point of substance is 202.8 K
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