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Question 6 (6 points) Calculate the normal boiling point of a substance in Kelvin to 4 significant figures given the followin
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Answer #1

Given that

\Delta H = 14.50 KJ/mol

\Delta S = 71.50 J/mol.K = 71.50 / 1000 KJ/mol.K = 0.0715 KJ/mol.K

Boiling point can be calculated by the following formula,

For vaporisation

\Delta G = \Delta H -T\Delta S = 0

\Delta H -T\Delta S = 0

\Delta H =T\Delta S

T= \Delta H / \Delta S

T = (14.50 KJ ) / ( 0.0715 KJ/mol.K) = 202.8 K

Hence the boiling point of substance is 202.8 K

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