Suppose the population grows (in thousands) according to the following relationship, P=125e0.012t , where t is...
Suppose the population grows (in thousands) according to the following relationship, P=125e0.012t , where t is the number of years. Using logarithms, find the number of years t, it would take for the population P, to double, that is equal 250. Also comment on the meaning of the exponent
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Suppose the population grows (in thousands) according to the
following relationship, P=125e0.012t , where
t is...
ASAP please 3. Suppose the population grows (in thousands) according to the following relationship, P=125e9.012, where...
ASAP please
3. Suppose the population grows (in thousands) according to the following relationship, P=125e9.012, where t is the number of years. Using logarithms, find the number of years t, it would take for the population P, to double, that is equal 250. Also comment on the meaning of the exponent.
1. Solve the following simultaneous equations (i) graphically and (ii) using the elimination method. (a) ...
1. Solve the following simultaneous equations (i) graphically and (ii) using the elimination method. (a) 2x + 3y = 12.5 (y on the vertical axis) (b) 4P – 3Q = 3 (p on the vertical axis) -x +2y =6 P +2Q = 20 2. Suppose the demand and supply of a good are given as P = 80 – 2Q and P=20 + 4Q (a) Calculate the equilibrium price and quantity, algebraically. (b) Suppose a per...
The population P of a city grows exponentially according to the function P(t) = 8000(1.2) Osts...
The population P of a city grows exponentially according to the function P(t) = 8000(1.2) Osts where t is measured in years. (a) Find the population at time <= 0 and at time <= 2. (Round your answers to the nearest whole number.) PCO) P(2) - (b) When, to the nearest year, will the population reach 16,000? yr
Suppose a population is growing according to the logistic formula N = 510/1+3e^-0.41t where t is ...
Suppose a population is growing according to the logistic formula N = 510/1+3e^-0.41t where t is measured in years. (a) Suppose that today there are 250 individuals in the population. Find a new logistic formula for the population using the same K and r values as the formula above but with initial value 250. (Round equation parameters to two decimal places.) (b) How long does it take the population to grow from 250 to 360 using the formula in part...
A population numbers 17,000 organisms initially and grows by 1.1% each year. Suppose P represents population,...
A population numbers 17,000 organisms initially and grows by 1.1% each year. Suppose P represents population, and t the number of years of growth. An exponential model for the population can be written in the form P = a: 6 where P=
- A population grows at a rate P' (t) = 300t e where P(t) is the...
- A population grows at a rate P' (t) = 300t e where P(t) is the population after t months. a. Find a formula for the population size after t months, given that the population is 3000 at t=0. b. Use the answer from part a to find the size of the population after 7 months. a. Find a formula for the population size after t months, given that the population is 3000 at t=0. P(t) = (Type an exact...
In t years, the population of a certain city grows from 500,000 to a size P...
In t years, the population of a certain city grows from 500,000 to a size P given by P(t) = 500,000 + 8000+?. dP a) Find the growth rate dt b) Find the population after 10 yr. c) Find the growth rate at t= 10. d) Explain the meaning of the answer to part (c).
A population numbers 14,000 organisms initially and grows by 8.8% each year. Suppose P represents population,...
A population numbers 14,000 organisms initially and grows by 8.8% each year. Suppose P represents population, and t the number of years of growth. An exponential model for the population can be written in the form P = a.b' where P = If 24500 dollars is invested at an interest rate of 10 percent per year, find the value of the investment at the end of 5 years for the following compounding methods, to the nearest cent. (a) Annual: $...
Suppose that a population of hacteria grows according to the logistic differential equation dP =0.01P-0.0002P2 dt...
Suppose that a population of hacteria grows according to the logistic differential equation dP =0.01P-0.0002P2 dt where Pis the population measured in thousands and t is time measured in days. Logistic growth differential equations are often quite difficult to solve. Instead, you will analyze its direction field to acquire infom ation about the solutions to this differential equation. a) Calculate the maximum population M that the sumounding environment can austain. (Note this is also calked the "canying capacity"). Hint: Rewrite...
1. The population of Sasquatch (in thousands), P(t), t years after 2015 is given by: 120...
1. The population of Sasquatch (in thousands), P(t), t years after 2015 is given by: 120 P(t) 13e-0.05t t > 0 (a) Find and interpret P(0). an expression for P'(t). (b) Find and simplify (c) Find and interpret P'(0). (d) Use P(0) and P'(0) to approximate the Sasquatch population in 2017.
1. The population of Sasquatch (in thousands), P(t), t years after 2015 is given by: 120 P(t) 13e-0.05t t > 0 (a) Find and interpret P(0). an expression for...
ASAP please
3. Suppose the population grows (in thousands) according to the following relationship, P=125e9.012, where t is the number of years. Using logarithms, find the number of years t, it would take for the population P, to double, that is equal 250. Also comment on the meaning of the exponent.
The population P of a city grows exponentially according to the function P(t) = 8000(1.2) Osts where t is measured in years. (a) Find the population at time <= 0 and at time <= 2. (Round your answers to the nearest whole number.) PCO) P(2) - (b) When, to the nearest year, will the population reach 16,000? yr
A population numbers 17,000 organisms initially and grows by 1.1% each year. Suppose P represents population, and t the number of years of growth. An exponential model for the population can be written in the form P = a: 6 where P=
- A population grows at a rate P' (t) = 300t e where P(t) is the population after t months. a. Find a formula for the population size after t months, given that the population is 3000 at t=0. b. Use the answer from part a to find the size of the population after 7 months. a. Find a formula for the population size after t months, given that the population is 3000 at t=0. P(t) = (Type an exact...
In t years, the population of a certain city grows from 500,000 to a size P given by P(t) = 500,000 + 8000+?. dP a) Find the growth rate dt b) Find the population after 10 yr. c) Find the growth rate at t= 10. d) Explain the meaning of the answer to part (c).
A population numbers 14,000 organisms initially and grows by 8.8% each year. Suppose P represents population, and t the number of years of growth. An exponential model for the population can be written in the form P = a.b' where P = If 24500 dollars is invested at an interest rate of 10 percent per year, find the value of the investment at the end of 5 years for the following compounding methods, to the nearest cent. (a) Annual: $...
Suppose that a population of hacteria grows according to the logistic differential equation dP =0.01P-0.0002P2 dt where Pis the population measured in thousands and t is time measured in days. Logistic growth differential equations are often quite difficult to solve. Instead, you will analyze its direction field to acquire infom ation about the solutions to this differential equation. a) Calculate the maximum population M that the sumounding environment can austain. (Note this is also calked the "canying capacity"). Hint: Rewrite...
1. The population of Sasquatch (in thousands), P(t), t years after 2015 is given by: 120 P(t) 13e-0.05t t > 0 (a) Find and interpret P(0). an expression for P'(t). (b) Find and simplify (c) Find and interpret P'(0). (d) Use P(0) and P'(0) to approximate the Sasquatch population in 2017.
1. The population of Sasquatch (in thousands), P(t), t years after 2015 is given by: 120 P(t) 13e-0.05t t > 0 (a) Find and interpret P(0). an expression for...
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