Question

can you help me solve these 2 questions please

O Rank the following substances in order of inacasing molar Solubility 14 - Smallest molar solubility ; S=largest molar solubility) in water at 25°C Ballz Ksp=4.0.x20? Balott), Ksp=s.0x103 Ksp = 7.9x10 to SoFz Mg(OH)2 Ksp = 8.9810-12 Ksp= 2.5810-10 2+ Culoz @ For the aqueous I Hg (NH3)4]? complex has a Keles Xlo" at 25°C Suppose equal volumes of 0.0082 m Hg(NO3)2 Solution and 0.72 m Ntz solution were mixed Calculate the equilibrium concentration (M Or aqueous Hght in

Answer 1

ky - Elegant 0.0082-2) (Hgat) 19:34 n(0.6872724 Assances 0.0082, 0.6872777 1.8x1019 0.0082 mx (0.6872)4 1. fx1019 d. 6872 1.237 x 10 19 0.0082 150.85 x 10019 0.0082 2) n a 0.0082 1.8x1096.223 0.0082 1.8x2019 x 0.6872,4 0.0082 0.401 x 109 0.02 x 1019 She equilibrium concentrate, It aqueous Hg at 0.2x10-20m k = 0.2x10 20 e as tight ion is

m2 2.225 x 10-12 2u a mlote keq - 8.98156 uglom az uge 200 kep- 8.9x10 12 - 4n3 8.9x10 12 kep klp - six2n R 4 2n 2 1.30 x 20 4 2 hep=2.5 x10 to evolt oloon. St2 kep= 7.9x1010 Be Free 3.24 +25 & bar) [E-32 nau? 7.9 x 1010 - 473 ou32 7.9x10 to 4,0 1.9961010 2 19.75×10 9 alna 42.7x10 3 (Befy) - 2.7x103 more luchat + coz kepe ² = 2.500 to (Thy 6), 1.30x10 t way . thidejo alon 1.58x105 7 m = horrol 2 molare 24 Tucz] 1.88x105 mon Any smallest molare solubility culo 1:58x105 more I Largest solubility BaOH) = 1.077x10 mone R-(for the agueny (je (1397 cauglen has a kg = 1.8x1079 at 25c. suppose qual volumes of 0.0082m the somtion, and 0.72m Ntly contlog were mined calentase the equilibrium concentration of aguay Hg 24 cês. 4g + trang (1364) Ja An equillibrorum 1.81 24 to AN Intial 0.0082 Concentration of completo; o 400-6872 +40 amount & pb Neith resired to complety win p2tr 4x9.0082 0-687274x 0·0082-1 -0.0328m concentret af 0.72-0.03 0.6872m 2+ 0.72M 0.0082 Change Nithya

molar sol moles sol Raon the following Substances in order of cricreasing solubility 2- smallest melere solubility & - Largest solebility et en watersch Bacoz keep = 4.0x109 Ba(OH)2 ksp = 5.0*103 SC F2 Mgoma respa flow w Cuco 7.9x10 10 keep = 8igx 2012 hipp : 2.5x10 to Baco Bar e fico cass Cases Baroney Bertest 2016 12 ta tu 6 Ju ونا n 2x keep = (Bazt]" COH)2 upa xxx H) (Br) 4. 0x10 nxxn x2 = 4.0x10-9 6:0X703 - mob@x)? 2 en x4u²403 nu a (6.4x10 1072 20. 632x10-5 A Boce) – 6.300 Moly b. n3, .5.9x10? ST 4. 1.077 101 (Barok)] = 1077x10) I na