Question

QUESTION 9 у 10 in. A F B T х

Answer 1

solution 1 10m Given syt = yield stoongth = 43 kpsi D = 2 in kt = 2, kts = 28 F =0 P = 3000 lbf T= 1000 lbim Now, considor the they Stopes demont, 3-D Layz zny 62 2 - since, F=0 then shear force is zero everywhose mi the beam and hence shear stoees due to bonding will be zero

d) Using momen principal storce theory, • Load p will produce axial strees in the direction of a. P Р A -D2 Tr т 3000 = 6790.61 s 4 (075) 6.79 KPsi -> Torque T will pseduce shear stoces on the bcom which is given by Day = radius of beam 5 = Polore moment of mostia We com see is zero Try at at r=0, so Tay will be zero. Since , point B is at the contor. that, B (729)g 13.58 kpsi 67 x kt = 6.79x2 = (6)B 13.58 k Psi b) from state of strees doment we can see that = 13.58 kpsi Yzx=0 √²+ 62 + 3 ay Von- mises streep 3.166 omon & Sut 43 -) FOS = FOS 13.58 FOS = factor of safety