Question

3. [-/3 Points] DETAILS LARCALC11 7.6.005.MI.SA. This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, skipped part Tutorial Exercise Find the center of mass of the point masses lying on the x-axis. m = 7, m2 - 3, m3 = 7 *1 = -5, X2 - 0,*3 = 4 Step 1 Let m, be the mass of the ith element and be the position of the /th element. Recall that the center of mass is given by * 1 m and 1 y = Since all the point masses lie on the x-axis, we know that y- Submit Skip you cannot come back)

Answer 1

Anso Let mi be the mass 0 of ita element and xi be the position of ith element. Then the x and y Coordinate of center of Mass is given by : h > x = X = { mini ial and امه = 3 mi ici n z mi AR! In grin question: m1=7 m₂ = 3, ma=7 x=-5, = 0, 43=4 so se= mix, tmak 2 + m 343 7*65)+ 3x(0) +7214) mitme+m3 7+3+7 = -35+0+28 17 since all boin't Mass lie on nanis, so y=10] so center of mass of boint mass lying -7 17 xanij is (5,9) =(-3,0)