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6. How many grams of Fe(OH)2 [Ksp = 1.8 x 10-1S) will dissolve in 1.0 liter of water buffered at pH = 10.26? ,inco 1-001 s ni
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Answer #1

PH= 10126 80 POH= 14-PH - 0 POH= 14- 10.26 > poH= 3.74 - and [ofr] can be determined by Poh. 80 Por= -log to [04] V 3.745 109solving for X The only real value is X=5.434 x 10 la 10 80 solubility - 50434 X 10 Mole x 89.86 gom Mole L 8 - solubility = 4

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6. How many grams of Fe(OH)2 [Ksp = 1.8 x 10-1S) will dissolve in 1.0 liter...
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