In this question AgI is given but molar mass of AgCl is given. I am using this molar mass only.
AgI
Ag+. +. I-
Ksp = [Ag+] [I- ] = 1.8 * 10-10
let molar concentration of ions be s M
Ksp = s * s = 1.8 * 10-10
s =
1.8 * 10-5 = 1.34 * 10-5 M
1.34 * 10-5 M means 1.34 * 10-5 moles are present in 1 litre
1 litre or 1000 ml contains 1.34 * 10-5 moles of AgI
For 500 ml, no of moles = 1.34 * 10-5 * 500/ 1000 = 6.708 * 10-6 moles
Number of moles = mass taken / molar mass
6.7 * 10-6 = mass taken / 143.35
Mass taken = 143.35 * 6.7 * 10-6 = 9.6 * 10-4 g
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