How many grams of PbI2 can be dissolved in 800 mL of a 0.100 M KI solution at 25 oC? Ksp= 7.90*10^-9 I have the correct...

Question

Question

How many grams of PbI₂ can be dissolved in 800 mL of a 0.100 M KI solution at 25 ^oC? Ksp= 7.90*10^-9

I have the correct answer of 1.38×10^-3 G, I just need to know how to get there.

Answer 1

Answer #1

kap (P6I2] = 7.9x109 volume of HI solution - 8oome Concentration of KI Solution colm KI kr + IT Concentration of Ir = [KI] Pb

Answer 2

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