Question

(4 points) The KSP for AgCl is 1.8 x 10-10 in which of the following would you expect AgCl to have the lowest solubility? (Circle one). д) 0,025 M Baci, b) 0.040 M AgNo, c) 0.040 MKCI d10050 MKCN e) 0.075 M HCIf pure water

very urgent !

Answer 1

The solubility will eventually decrease as a result of common ion effect when, BaCl2, AgNO3, HCl, KCl are added as they contains common cation or common anion. More is the concentration of the common ion more becomes its effect on the solubility of AgCl.

In this context,

BaCl₂ produce,(2x 0.025)M = 0.05M Cl^- ion (common anion)

0.040M AgNO₃ gives, 0.040M Ag⁺ ion (common cation)

0.040M KCl forms 0.040M Cl^- ion (common anion)

0.075M HCl forms 0.075 M Cl^- ion (common anion)

Thus, the solubility of AgCl will be lowest in 0.075M HCl as it produces more number of chloride ion