Question

What is the solubility of AgCl in pure water at
25°C? The Ksp of AgCl is 1.8x10^-10.

9.0 x 10^-11
1.3 x 10^-5
1.8 x 10^-3 3.6 x 10^-10

What is the solubility of AgCl in 10 M NH3? The Kf of Ag(NH3)2+ from AgCl(s) in aqueous NH3 is 0.0031, which is for the balanced reaction shown below.

AgCl(s) + 2 NH3(aq) → Ag(NH3)2+(aq) + Cl-(aq)

Kf = 0.0031

0.176 M
0.426 M
0.023 M
0.557 M

Answer 1

AgCl --------> Ag⁺ + Cl^-
Ksp = [Ag⁺][Cl^-] = 1.8 x 10^-10
The molar solubility of AgCl = [Ag⁺]

in pure water
Let [Ag⁺] = x. Then [Cl^-] = x, and substituting in the Ksp expression we have
(x)(x) = 1.8 x 10^-10
x² =1.8 x 10^-10
x = 1.342 x 10^-5 moles dm^-3 = molar solubility of AgCl
Molar mass of AgCl is 143.321 g /mol
solubility = 143.32 g / mol x 1.342 x 10^-5 moles dm^-3
= 1.8 x 10^-3 gdm^-3