Consider the rate law.
rate=k[A]^x
Determine the value of x if the rate doubles when [A] is doubled.
x=
Determine the value of x if the rate quadruples when [A] is doubled.
x=
Consider the rate law. rate=k[A]^x Determine the value of x if the rate doubles when [A]...
For the reaction: A rightarrow B + C and a Rate Law of: Rate = k [A]^X, determine the value of x in each of the following cases: WHY? a. There is no rate change when [A] is tripled b. The rate increases by a factor of 9 when [A] is tripled c. When [A] is doubled, the rate increases by a factor of 8
7. Consider the following reaction A+B - products. The rate law was found to be Rate = k [A] [B]. Calculate k if [A] = 0.0500 M [B] = 0.125 M and the reaction took 405 seconds to go to completion. 8. For a reaction A+B → C, doubling the concentration of either A or B, quadruples the reaction rate. Write the rate law for the reaction.
Question 25 2.5 poir The rate law for a chemical reaction is rate = k[X] [7). If the reaction is run and then it is repeated with the concentration of X doubled and the concentration of Y doubled, the rate of the reaction will be a four times faster Ob. six times faster Oc. eight times faster d. two times faster
What is the value of k for a reaction that has the rate law rate = k (X)2(Y)0 When the following data was collected Concentration of X = 0.136 M Concentration of Y = 0.137 M Initial rate = 0.87 M/s
Determine the rate law and the value of k for the following reaction using the data provided. 2 NO(g) + Br2(g) → 2 NOBr(g) [NO]i (M) [Br2]i (M) Initial Rate (Ms-1) 0.030 0.0055 1.81 x 10-2 0.030 0.0110 3.62 x 10-2 0.060 0.0055 7.25 x 10-2 please show step by step.
consider the rate law below. what is the value of the rate constant ... 1. Consider the rate law below. What would happen to the rate constant if the initial concentration of B was doubled? Rate k [A][B]2 Use the following information to solve the question below. Initial Rate (M/s) Exp [A] M [BIM 1 0.20 M 0.000066 0.30 M 0.000132 2 0.20 M 0.60 M 0.000264 3 0.40 M 0.30 M What is the value of the rate constant?...
What are the units of k in the following rate law? Rate = k[x][y]^2 1/M s^2 1/M^2 s M^2 s M^2/s 1/M^3 s Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = k [X][Y]^2 the rate reaction will increase by a factor of 2 The rate of reaction will increase by a factor of 4. The rate of reaction will increase by a factor of 5. The rate...
Question Determine the rate law and the value of k for the following reaction using the data provided. 1/1 point 2 N2O5 - 4 NO2+O IN20sl (M) initial Rate (M-1,-1) 0.093 4.84 x 10-4 0.084 4.37 x 10-4 0.224 1.16 x 10-3 Rate - 6,0 x 10-1M2-1N205) Rate -5.2 x 10-3541N205) Rate - 5.6 x 10 2 M15-41N20512 Rate - 1.6 x 10-3 M1/2,-41N20511/2 Rate - 1.7* 10-2M-1/2--IN20513/2
Part A Determine the rate law and the value of k for the following reaction using the data provided: 2NO(g) + O2(g) + 2NO2(9) [NO]; (M) [Ogl (M) Initial Rate (M4 st) 0.030 0.0055 8.55 x 103 0.030 0.0110 1.71 x 10-2 0.0055 3.42 x 10-2 0.060 Rate = 3.1 x 105 M-3 s[NO]2[0212 Rate = 57 M' s'[NO][O21 Rate = 9.4 x 103 M25 *[NO][0212 Rate = 3.8 M-1/2 s [NO](O2) 1/2 Rate = 1.7 x 103 M2 s?[NO]2[02]
For cases where [A] exactly doubles: • if the rate does not change, the order for A is 0. • if the rate doubles, then the order for A is 1. • if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: ratei [reactant), order rate '[reactant]2 What is the reaction order with respect to A? [A], mol/L [B], mol/L Trial 1 0.694 0.432 rate, mol/(L-min) 0.0752 Trial 2 1.39 0.432 0.0752...