A spring with a force constant of 1.50 N/m is attached to a mass of 120g. The system has a damping constant of 0.0180 Ns/m. How long does it take the amplitude of the oscillations to
decrease from 10.0 mm to 5.00 mm?
Please show step by step work
A spring with a force constant of 1.50 N/m is attached to a mass of 120g....
A 3.33-kg mass attached to a spring with k = 151 N/m is oscillating in a vat of oil, which damps the oscillations. If the damping constant of the oil is b = 10.3 kg/s, how long will it take the amplitude of the oscillations to decrease to 1.70 % of its original value? What should the damping constant be to reduce the amplitude of the oscillations by 98.3 % in 1.30 s?
A 0.500 kg mass is attached to a spring of constant 150 N/m. A driving force F(t) = ( 12.0N) cos(ϝt) is applied to the mass, and the damping coefficient b is 6.00 Ns/m. What is the amplitude (in cm) of the steady-state motion if ϝ is equal to half of the natural frequency ϝ0 of the system?
A 600-g object is attached to a spring with a force constant of 2.4 N/m. The object rests on a horizontal surface that has a viscous, oily substance spread evenly on it. The object is pulled 15 cm to the right of the equilibrium position and set into harmonic motion. After 3 s, the amplitude has fallen to 7 cm due to frictional losses in the oil. Calculate the following. a. The natural frequency of the system b. The damping...
: When a 3 kg mass is attached to a spring whose constant is 12 N/m, it comes to rest in the equilibrium position. Starting at i=0, a force equal to f(t) = 15e-54 cos 4t is applied to the system. In the absence of damping, (a) find the position of the mass when t=n. (b) what is the amplitude of vibrations after a very long time?
: When a 3 kg mass is attached to a spring whose constant is 12 N/m, it comes to rest in the equilibrium position. Starting at i=0, a force equal to f(t) = 15e-54 cos 4t is applied to the system. In the absence of damping, (a) find the position of the mass when t=n. (b) what is the amplitude of vibrations after a very long time?
When a 6 kg mass is attached to a spring whose constant is 54 N/m, it comes to rest in the equilibrium position. Starting at i = 0, a force equal to f(0) = 30e-7t cos 6t is applied to the system. In the absence of damping, (a) find the position of the mass when t= 1. (b) what is the amplitude of vibrations after a very long time?
When a 5 kg mass is attached to a spring whose constant is 45 N/m, it comes to rest in the equilibrium position. Starting at t= 0, a force equal to f(t) 30e-3t cos 4t is applied to the system. In the absence of damping, (a) find the position of the mass when t= 1. (b) what is the amplitude of vibrations after a very long time?
When a 6 kg mass is attached to a spring whose constant is 54 N/m, it comes to rest in the equilibrium position. Starting at 1 = 0, a force equal to f(t) = 30e-7t cos 6t is applied to the system. In the absence of damping. (a) find the position of the mass when t=1. (b) what is the amplitude of vibrations after a very long time?
When a 6 kg mass is attached to a spring whose constant is 54 N/m, it comes to rest in the equilibrium position. Starting at i = 0, a force equal to f(0) = 30e-7t cos 6t is applied to the system. In the absence of damping, (a) find the position of the mass when t= 1. (b) what is the amplitude of vibrations after a very long time?
When a 4 kg mass is attached to a spring whose constant is 100 N/m, it comes to rest in the equilibrium position. Starting at t= 0, a force equal to f(t) = 12e-3t cos 6t is applied to the system. In the absence of damping, (a) find the position of the mass when t= 1. (b) what is the amplitude of vibrations after a very long time?