Calculate the Ka (aq., 25 °C) of a 0.250 M weak acid whose pH is 3.86....
A weak acid, HA, is a monoprotic acid. A solution that is 0.250 M in HA has a pH of 1.890 at 25°C. HA(aq) + H2O(l) ⇄ H3O+(aq) + A-(aq) What is the acid-ionization constant, Ka, for this acid? What is the degree of ionization of the acid in this solution? Ka = Degree of ionization =
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you very much! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thanks guys! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4 at 25.0...
Hey guys, I am having a lot of trouble with my homework. Could you please help? I thumbs up anyone who gives a thorough explanation and shows the work! I really need to understand these concepts! Thank you! 1) Z- is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Kb of Z- is: 2) The base-ionization constant of ethylamine (C2H5NH2) is 6.4 x 10-4 at 25.0...
8) The base-ionization constant of ethylamine (C2H-NH2) is 6.4 x 10-4 at 25.0 °C. The [H*] in a 1.6 x 10-2 M solution of ethylamine is M. 9) Z is a weak base. An 0.350 M aqueous solution of NaZ is prepared. The pH of the solution was 8.93 at 25.0°C. The Ky of Z" is: 10) At 25 C, the pH of a 0.15 M aqueous solution of Csz (the cesium salt of HZ) is 10.70. What is the...
1. Calculate the pH at 25°C of a 0.757 M solution of a weak acid that has Ka = 9.28 x 10 2. Determine the Kb of a weak base if a 2.50 M solution of the base has a pH of 9.595 at 25°C. 3. The overall dissociation of malonic acid, H2C3H2O4, is represented below. The overall dissociation constant is also indicated. H2C3H204 = 2 H+ + C3H2042- K = 3.0 x 10-9 To a 0.025-molar solution of malonic...
Consider the following data on some weak acids and weak bases: acid name Ka formula base Ko name formula ethylamine C2H5NH2 6.4 x 10-4 hydrofluoric acid HF 6.8 x 10-4 acetic acid HCH3CO2 1.8 x 10-5 methylamine CH3NH2 4.4 x 10-4 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the...
Consider the following data on some weak acids and weak bases: acid Ka name formula HCH,CO2 1.8 x 10-5 base name formula pyridine C;HEN 1.7x10-9 ethylamine C2H5NH2 6.4 x 10-4 acetic acid hypochlorous acid HClO 3.0 x 108 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH,...
Consider the following data on some weak acids and weak bases: acid base Ka Кь name formula name formula -4 hydrofluoric acid HF 6.8 x 10 ammonia NHZ -5 1.8 x 10 4 HNO2 4.5 x 10 -4 nitrous acid ethylamine C2H5NH2 6.4 x 10 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution...
Calculate the pH during the titration of 20.00 mL of 0.1000 M CH3COOH(aq) with 0.2000 M NaOH(aq) after 2.5 mL of the base have been added. Ka of acetic acid = 1.8 x 10-5. QUESTION 9 Calculate the pH during the titration of 30.00 mL of 0.1000 M ethylamine, C2H5NH2(aq), with 0.1000 M HCl(aq) after 26 mL of the acid have been added. Kb of ethylamine = 6.5 x 10-4. QUESTION 10 Calculate the pH during the titration of 20.00...