C2H5NH3Br is conjugate acid of C2H5NH2
So, its pH would be less than 7
KCH3CO2 is conjugate base of CH3CO2H
So, its pH would be more than 7
NaF is conjugate base of HF
So, its pH would be more than 7
KCl is neutral salt.
So, its pH would be 7
KCH3CO2 is stronger base as compared to NaF because Ka of HF is
more.
So, pH of KCH3CO2 will be more than pH of NaF
Answer:
C2H5NH3Br: 1
KCH3CO2: 4
NaF: 3
KCl: 2
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