NaF is conjugate base of HF
So, its pH would be more than 7
CH3NH3Cl is conjugate acid of CH3NH2
So, its pH would be less than 7
KNO2 is conjugate base of HNO2
So, its pH would be more than 7
NH4Br is conjugate acid of NH3
So, its pH would be less than 7
NH4Br is stronger acid as compared to NH4Br because Kb of CH3NH2 is more.
So, pH of NH4Br will be less than pH of CH3NH3Cl
NaF is stronger base as compared to KNO2 because Ka of HF is more.
So, pH of NaF will be more than pH of KNO2
Answer:
NaF: 4
CH3NH3Cl: 2
KNO2: 3
NH4Br: 1
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