Question

А NaOH Heated KOH Reagent Reapeut Product 1 Hgso/H.O H Br/h 144a HLV Pa at 2.H0 . LDA OH CI: Repeat 1.) Su BH Product 2 2.)H,O, NOH NBS/

Answer 1

are that are missing Bralho H. (2) For the ginen question, the reagents that and products Reagent (2) - Product (1) - En Reagent a Reagent 3 =) C = 1.) Na NHal heat 2. H2O Prodruct 2 & E= I I LDA ce Thus, By LDA Bralnu (Reagent) U el NaNH₂ that (prod. 1) (Reagents) ercayal? | 63 m2 1. Slag BH 2 H₂007 Naon (product 2)

the o el rotation The Reagent I leads to 'bromination of the alkame through to radical formation, giving a more stabile allye halide The alkge halide in the attacked by chindered bare LDA, forming terminal alkene. The encond third reagent there, i.e NaNH2 forms terminal allagne from nicinal dihalides. The terminal The terminal alegne finally undergoes hydrofor atèn onidalion có gine the final product. exclusively Fast

50% H₂Sou H2O product. Mech دے کہ + Ho imone stable cation) H₂o. o asti 120 product H₂O + Thus, option À is correct