Question

Your answer is partially correct. Try again. Find an equation for the tangent plane and parametric equations for the normal line to the surface at the point P. 2=*+y: P(1, -3,10) Tangent Plane: 2x -6y-10 Edit Normal Line: X(t) = 1 +21 Edit Edit y -3-2t z(t) = 10-1 By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor © 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc.

Answer 1

Z= 2²ty? » solution- at p(1-3,10) Leat f(x, y, z)= x² + y²2 Let surface flay,z) zo Tangent plane: at (2,3,7) then tangent plane Een El. lat (2, B8) Oy (2-2) fx + (y-p) fy + (2-8) £ so, o Fx = 20 fy=24 f2=-1 Q,B,Y)= (1, -3,10) and So, (8%) - DF H1, -310) (2-1) E420) + (y+3] [{x}er, 3 boy + (Y+3) (fix) ev, on +2+0) lahkusia (1-1) (201 +(V+3) ( 26-3 + 2-10) 6-1)=0 (22-2) +(-67-18) - Z +10=0 27 - 6Y-Z -10=0 oy [z = 2X-6Y-10]

Z_Y » Equation of Normal line: (8-8) x DF |(2,6,8) Y-B Fy fx F2 Pa (1-3,16), fy (1,-3,60), fã (1.-3,10) TODY <2,-6, -17 VE Z-10 11-1 2 Y+3 -6 = + (sey 2=2+ +1 X=67-3 (Answer Z--tto

Thanks and Happy learning.

ask me if you have any doubts.......please rate my answer....