Question

A Carvas А D Question 3 20 pts What is the maximum value can be to the nearest 0.01 k? Assume all cross sectional members are square, A-35 in? E = 25,000ksi Fy - 42 ksi 26 in 54in - Previous Next 51 F A # 3 $ 4 % 5 & 7 6 * 8 2 9 0 W E R T Y U 0 S D F G H. к

Answer 1

Calculate the force in each member in follous: Apply equilibrium equilibrium conditions as shown: terms of p as E MA = 0 PX27 - VRX 54 = 0 VB = 0.5P member for joint in me tensile force B Cassume from Bo as awow С Efy 26 FBc x +0.5P = 2627272 FBC 0.7 208P c

= fx=0 27 FBcx Х 126²+272 + FBA = 0 FBA= -FBcx 27 262 +272 0.7208 *P * 27 (262+272 FBA 0.51927 FAC = -0.7208 P -7205 P Csymme Maxingum force ce = fj - Ej x A 42X35 00 720 8p P 2039.400k
Initialy we need to find force in each member in terms of P

Using equilibrium equations we can find force in each member

Now using equation,

Maximum force=Fy×A

Here Maximum force is 0.7208P

So on equating we can find the Maximum value of P

P=2039.400K