Question

E. Last Number time limit per test: 1 second memory limit per test: 256 megabytes input standard input output standard output You are given a sequence of positive integers aj, , 03, ... Print the last element of the sequence. Input The input consists of multiple lines. The i-th line contains a single positive integer a: (1 <a < 1000). The input ends with a line consisting of a 0, which indicates the end of input. Zero is not an element of the sequence. The input consists of at least 2 lines and at most 1000 lines. Output Print a single integer - the last element of the given sequence. Examples input Copy output Copy input Copy 8 0 output Copy input Copy 10 101 57 1000 1 333 555 0 output Copy

I want this using while loop

This using stringin python

Use list or some thing in python

Using list in python
I want answer as soon as posdible

Answer 1

Last number code:

l = []  #initialising l with empty list
while True: 
    n = int(input())    #taking integer as an input
    if n == 0:  #if n is 0 exiting the loop
        break
    l.append(n) #adding elements to list l at the end
print(l[-1])    #-1 is the index of last element of list

Code Screenshot:

1 = [ #initialising 1 with empty list while True: n = int(input()) #taking integer as an input if n == 0: #if n is 0 exiting the loop break 1.append(n) #adding elements to list l at the end print (1[-1]) #-1 is the index of last element of list

Output:

=== === RESTART: C:/Users/VSNK/AppData/Local/Programs/Python/Python37/foajf.py 10 101 57 1000 1 333 555 0 555 >>>

Middle digit code:

n = input() #taking number as a string
mid = len(n)//2     #calculating the mid position
print(n[mid])   #printing the middle digit

Code Screenshot:

n = input() #taking number as a string mid = len (n)//2 #calculating the mid position print (n[mid]) #printing the middle digit

Output:

=== === RESTART: C:/Users/VSNK/AppData/Local/Programs/Python/Python37/aojga.py 3619437 9 >>>

Consecutive same signs integers code:

n = int(input())    #taking number of integers to take as input
l = input().split()#taking spaced integers as string and splitting them by space
for i in range(n):
    l[i] = int(l[i])#converting string to integer in list
flag = False    #initially assuming there are no consecutive same signs 
for i in range(n-1):    #traversing upto last but one element index
    if l[i]*l[i+1] > 0: #if current element and next element are of same signs
        flag = True     #then flag is turned to True
        break   
if flag == True:    #if flag true then printing YES
    print("YES")
else:               #else NO
    print("NO")

Code Screenshot:

n = int(input()) #taking number of integers to take as input 1 = input().split() #taking spaced integers as string and splitting them by space for i in range (n): 1[i] = int(1[i]) #converting string to integer in list flag = False #initially assuming there are no consecutive same signs for i in range (n-1): #traversing upto last but one element index if l[i]*l[i+1] > 0: #if current element and next element are of same signs flag = True #then flag is turned to True break if flag == True: #if flag true then printing YES print ("YES") else: #else Nd print ("NO")

Output:

=== === RESTART: C:/Users/VSNK/AppData/Local/Programs/Python/Python37/aohg.py 4 -1 5 7 -4 YES >>> RESTART: C:/Users/VSNK/AppData/Local/Programs/Python/Python37/aohg.py 3 -7 9 -6 NO >>> === ===

Alexa code:

n = int(input())    #taking number of integers to take as input
l = input().split()#taking spaced integers as string and splitting them by space
for i in range(n):  
    l[i] = int(l[i])#converting string to integer in list
    if l[i]<0:      #if the integer is negative
        l[i] *= -1  #mutliplying it with -1 to convert it to positive
print(l)    #printing the list

Code Screenshot:

Output:

=== === RESTART: C:/Users/VSNK/AppData/Local/Programs/Python/Python37/oagja.py 5 1 5 -3 4-7 [1, 5, 3, 4, 7] >>> Activate Window

Each and everything is explained in the comment section of code.

Thank you! Hit like if you like my work.