Question

help with all 6 questions please

Question 24 1 pts An isotonic solution of NaCl is 0.90% w/v. Suppose you start with a teaspoon (5.69 g) of NaCl and dissolve it in water. How many total mL would the solution need to be to be isotonic? Give to at least two significant figures? Question 25 1 pts A soft drink has a pH of 2. What will be the concentration of Ht? Give the exact number, without the unit. I

Answer 1

on bala 2 Al(OH), Coylicia X 100 2 22) tritt X 100 amb fino 2 xme. as x me = 63202 ml. 2 Al(OH)3 + 3Hcl - Alel + H₂o. 24) 1o Mars of Nail 25.69 w/vt. of Nach 0.90-1. Wivu. Mass in g volume in me 5.69 0.90 0-90 5.69 5.69 X 100 0.10. 25) PH ph is nothing but negaline legarithm of hydrogen ion concentration pH 2 - log [HI] 1x100 0-2 21). Number of atom in. Number Atom Reactant en product 2 2 M 2 - log 14th 16). (CH from M 2. that of A town Atom & N. mole e forme + Al 1 1 H 3 1. 3 el

on balancing by trial and error method Al(OH) + 3 Hel - Alcl3 + 3H₂o. coefficient of water 23 2. God ml. 22). Initial volume, v concentration, My z 6.8M final volume, 2 40ml. 2 as nee know MINI M2 V2 2 6.8 X 6.1 2. 40 X M2 M₂ 6.8X 6-1 1.037. 2 2 4o. M₂ 21.037 mole one 1 : 3. are 16). (CH₃)₂NH₂ +2 N₂04 AH₂O +3 N, t2co, from the ginen equation, we can conclude that the stoichiometrie ration of (C) NH₂. & Nz is 7. e for every (CH ₃ ) 2 Natz 3 moles of Ne gas formed (CH3)2 Ng Hz. Hence for. 5.84 mol moles of Ne gas formed 3x5.84 2 17.52 moles mas mole of 2

H₂ + 4 + 4H₂0 & 4 K2544 of Mass Molar mass H₂Soq taken 2.5.16 gram. 1.008X2 + 32.07 + 16 X 9 2. 2. 2. 98.086gme. 5-16 grams of H2304 2 0.0526 moles from the given reaction. We can concluele Alan rakan molar fratio of H₂SO4 & is that KI 0.0526 alo 2, 2 2 2) 5x 0.052688 2 2 2 0.052688 z) x 20.08416 moles Hence moles kl required 0.08 & 16 moles Molar mass of kl 2.39.10 + 126.90. 1 166 gons. of 2 1 mol of kl 2 166 gms. mol of KI 13.97. gm. 0.08 416 2