Question

1. (2 pts) A saline solution contains 1.1 % NaCl by mass. How much NaCl is present in 96.3 g of this solution? 2. (4 pts) How many liters of a 0.500 M sucrose (C12H22011) solution contains 1.5 kg of sucrose? 3. (2 pts) To what volume should you dilute 25 mL of a 12 M stock HCl solution to obtain a 0.500 M HCl solution? 4. (2 pts) Write the formula for the conjugate acid of the following bases: a. NH3 b. CI04- 5. (5 pts) A 10.0 mL sample of an unknown H3PO4 solution requires 112 ml of 0.100 M KOH to completely react with the H3PO4 a. Write a balanced equation for the neutralization reaction that occurs. b. What was the concentration of the unknow H3PO4 solution?

Answer 1

Ans. 1 1-17% 14+ Nad solution by Maus. (mass) amount of Solution 96.39 % by mass = mass of solute xico mass of solutim XIDO mass of Nau 96.3 1.1x96-3 IBO mass of Nach May 4 Nach = Ans. 2 1.0997 Molarity 4 Sucrose solution = 0. Soom. of Sucrose = les Rg = 150g Molar 'mass of sucrose = 342 gmden' molarity mass of solute Molar mass of solute x volume Mass = solution (L) 0.5od = 1560 342 x volume volume = 8.77 Lihres 1500 342 X0.500 Amis 25 ml Molaity of original solution = 12m volume of original solution Molaity 4 diluted solution = 0.500m diluted solution UmL = (M272) dicuted volume using, (Mili) original 12x25 = 0.500 X U2 = 12 x 25 0.500 روا 112 - Goomy - upto Goome volleme original soluelim is diluted to make it upto o.soom

Ans.y conjugate acid :- The specie formed when after accepting a protou conjugate acid NH3 +40 Nay b) clou 40 Helou Auss 10.0mL voluence of Hz Poy Solution = concentration of Hypoy solution = C, volume of Kou required= 112 mL concentration of hou = 0.160 M. a) Balanced Neutralisation Reaction. H₂poy + 3 Nooh Na, poy + 340 (b (N2 V2) KOM using Normality equation. (NIV) HAPON (ngx 1 x Mx.U) Azrou = (nf xMxV) RoH. 3 x C, x 10 Na Normality ng = n-factor M= nolarity as N= ngxml ng (Hg poy) nf (KOH). = 1 = 3 | X0-100 X112 Ci= 1X0.100X112 3x10 |C, = 0.373 m