You have a 1 M solution of NaCl. How much do you need to dilute to...

Question

Question

You have a 1 M solution of NaCl. How much do you need to dilute to make 10 L of isotonic saline (0.9%)? Remember that the uni

Answer 1

Answer #1

Isotonic Solutions: These are the Solutions having same osmotic pressure.

Therefore,

Osmotic pressure of 1M NaCl = osmotic pressure of 10L NaCl solution.

Since, the solute in both the solutions is NaCl, the value of vanthoff factor 'i' is same .i.e., 2.

Now the formula becomes

C₁ = C₂

1M = ( Weight of NaCl/Molecular mass of NaCl) / (1000)/10,000 mL)

Weight of NaCl = (1M X Molecular of NaCl X 10,000mL) / 1000

Weight of NaCl = (1M X 58.5 g/mol X 10,000mL) / 1000

Weight of NaCl = 585 g.

The amount of NaCl required to get 1M of 10 L NaCl solution is 585 g.

Answer 2

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