Question

If two polynomials (2x³ + ax² + 4x -12) and (x³ + x² - 2x + a) leave the same remainder when divided by (x - 3) . Find the value of a and also the remainder.

Answer 1

When (2x²+ ax²+ 4X-12) is divided by (x-3) 2-3) 2 x tauc? + 4x-12 12 2 (2x? +(6+Q)X + +(22+3a) 2x² - 600² + noit (6+a)x+ 421-12 (6+2)x? 3 (6+a)) -121 + + 4x+(18+3 a)2-12 =(22+3 a)1-12 22 + 3a - 3122+3a) + + - 12+66+ 9 a - 54+ 9 a + K .. Remainder is 54 + 9 a - (E-)-1

Wher (a +2°- 24+ a) is divided by (4-3) 2-3) x3+x?_2a+a (x +4x +10 3 a-30² + 40²-2ata 4x²_12x + 10+ a 10x - 30 + 30ta 30+Q, 2 to question, در بازار Remainder is Now, acear a ceording 54 +9a = 30 +a - sa: -24 2 a=-3 dech 30+a Toner Remainder = 30-3 *dade 27
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