find the general solution of the differential equation
55y''''+224y''+225y=0
Given differential equation
The characteristic equation is:
This can be written as:
The roots are:
Therefore,
The general solution is:
find the general solution of the differential equation 55y''''+224y''+225y=0
Find the general solution of the differential equation. 55y (4) +224y'' +225 y=0 OB. osCicer to sim 2 ):0,cor (35 *)c(***) ? Cicos(v1 x)+czsin(*+c.cos( *$*]=Casin( tas *) ocGcos( *]=csin(Jin »)+ccos( *$*]=c_sin ( Te *) Oblico clc.com ***c*) ORG.COM(**+c=2 van 5-6com **)+cisim(*)
QUESTION 23 Find the general solution of the differential equation. 55y (4) +224 y'' +225y=0 08. Cicos/ х 04 Gicos(x)=(sin()=C.cos( 15 *}+c^5in ( 15 *) (1 x)+Czsin( *)+C;cos( **]+Casino OCG.com «Jocsi ( 1 * 16300(* *)+cisi ( *) vạn )+Ccos (Tox]+c=sin(x) os( *)+czsin(**]+C;cos( **]+Casim(**) OD. Cicos 5 x+C25 11 OECcos
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