11 Solve the following Initial Value Problem: dy dt 2t + sech 2y y(0) = -5
Solve the following Initial Value Problem: dy dt 2t + sect 2y y(0) = -5
(1 point) Solve the following initial value problem: dy + 0.6ty = 3t dt with y(0) = 5. y = (1 point) Solve the following initial value problem: dy dt + 2y = 3t with y(1) = 7. y
(Example 7.2.4) Use the Laplace transform to solve the initial-value problem 6. dy + 3-13 sin 2t, dt y(0)-6
Solve the following initial value problem: dy/dt+ 0.3ty=4t with y(0)=9.
Solve initial value problem (IVP) dy 2y- х dx V x2 – 16 = 0, y(5) = 2
Solve the initial value problem dy dx+2y-4e0y(O)2 The solution is y(x) Solve the initial value problem dy dx+2y-4e0y(O)2 The solution is y(x)
(1 point) Consider the initial value problem d2y dy 8 +41y8 cos(2t), dt dy (0) y(0) = -2 -6 dt dt2 Write down the Laplace transform of the left-hand side of the equation given the initial conditions (sA2-8s+41)Y+2s-18 Your answer should be a function of s and Y with Y denoting the Laplace transform of the solution y. Write down the Laplace transform of the right-hand side of the equation (-8s+32)/(sA2-8s+20) Your answer should be a function of s only...
Problem Thre: 125 points) Consider the following initial value problem: dy-2y+ t The y(0) -1 ea dt ical solution of the differential equation is: y(O)(2-2t+3e-2+1)y fr exoc the differential equation numerically over the interval 0 s i s 2.0 and a step size h At 0.5.A Apply the following Runge-Kutta methods for each of the step. (show your calculations) i. [0.0 0.5: Euler method ii. [0.5 1.0]: Heun method. ii. [1.0 1.5): Midpoint method. iv. [1.5 2.0): 4h RK method...
(1 point) A. Solve the following initial value problem: dy dt cos (t)-1 with y(6) tan(6). (Find y as a function of t.) (1 point) A. Solve the following initial value problem: dy dt cos (t)-1 with y(6) tan(6). (Find y as a function of t.)
d2y dy +10 dt +25y 0, y(1) 0, y'(1) 1 (1 point) Solve the initial-value problem dt2 Answer: y(t)