Homework Answers
(A). Only (I)
1. ∀x ((student(x) ^ walk (x)) → talk (x)))
for all x, IF(x is a student and if x can walk) THEN x can
talk.
Possible when the person is student and he is walking, only then he will talk.
2. ∀x (student(x) ∨ (walk (x) → talk (x)))
for all x, IF(x is a student or (if x can walk THEN x can talk)).
Wrong Implication.
3. ¬ ∃x ((student(x) ^ walk (x)) ^ ¬(talk (x))))
No implication is made in this statement as no → is there.
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