Question

Provide a sketch and state your assumptions as you determine the shape factor F12 for the following: Za=0.4 m Y = 0.3 m Zn = 0.2 m X-0.5 m

Answer 1

Solution- Given Data, * From the plate diogram Analysis in perpendicular Za=0.4m (4) Z=0.2m (3)': 2 X=0.5m * Let's a space part of the portion indicate (3) and (4) * Radiation of heat transfer from the Surface . relation is, Formulae: - → F4-2) x A1 = F (2-1) XA2 7 F (1-3) XA1 = F(3-1) XA 3 } (concklion). diagram Now, base on too Equation above the Gustamazed to calculate. 4 (52-4] A2[72-3) + 2 ] (2-1) = (F4-4 - 13-3] Simplified,

* Consider some basic Standard chart reference analysis. and 0.4 = fg-4 = Za Zo a - -0.8 0,5 "{{2-4) 0.3 = 0.6 y 0.5 =>* Fq -4 = 0.25 (chant values) 2-3 Fq- Zb 0.2 = 0.4 x 0.5 e 0.3 -0.6 x 0.5 = 0.16 (chart valuess) Chart: 0.5 y X0.3. 0.24 0.1 0.2 1x 0.4 0.6 0.8 4 6 8 10

F2-12 F2-4-[F2-3] 0.25 0.16 = F₂-1 fq-1 0.09 Then, He get apply the condition, {F1.2] x Al = [F2-1] *A2 => [F1 -2] * Co. 2 x0.5] : = [0.09] *[0.3x0.5 * (Fi-2 -0.135 Assumptions:- ① In the shape of factor sulation in Expression on two bodies heat transfer process with radiation Energy is Condition, Alfa *(1-2) of = A2 F-1) When onth Surface calculate part on radiation heat transfer Energy Ffr-n). find + F + F1.3 1-2 - ༡ཏེ། F2-1 + F2- 2 +F 2-3 "(1-0) fQ-n) = 2 Fr-1 + fn-2 + Fn-3 En-n) 1

radiation Energy 3 material of sadration from any it's required factor of Surface with Shape of Concave. 1st - Fu-1)=0 then fi-a=l 2nd Fiq-1) = AL A2 A, and A₂= area of Surface. 4 The Shape of factor is completly analysis of geometrical parameter input and out optimization 5. The material of convex shape of surface is unity combination intercepted on Enclosing surface of siodeation Energy, at's was not a vice versa operation. :: Hence proved the Solution.