In a simple random sample of 95 families, 70 had one or more pets at home....

Question

Question

In a simple random sample of 95 families, 70 had one or more pets at home....

In a simple random sample of 95 families, 70 had one or more pets at home. At the 1% level of significance, test the claim that the proportion of families with one or more pets differs from 60%. Calculate the test statistic, round your answer to two decimal places.

math Statistics-And-Probability

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

11 n=95 36=70 الدرو = 0.7368 95 d=0.01 claim: P 90.60 , P=0.50, 9-1-1=0.40 Ho: P=0.50 H, P+0,60 test Stectis tics, 2= -p reti

Add a comment

Answer 2

Similar Homework Help Questions

In a simple random sample of 95 families, 70 had one or more pets at home....

In a simple random sample of 95 families, 70 had one or more pets at home. At the 1% level of significance, test the claim that the proportion of families with one or more pets differs from 60%. Calculate the test statistic, round your answer to two decimal places.
In a simple random sample of 95 families, 70 had one or more pets at home....

In a simple random sample of 95 families, 70 had one or more pets at home. At the 1% level of significance, test the claim that the proportion of families with one or more pets differs from 60%.
Part 5 of 6 In a simple random sample of 95 families, 70 had one or...

Part 5 of 6 In a simple random sample of 95 families, 70 had one or more pets at home. Can you conclude that the proportion of families with one or more pets differs from 0.67 Determine the parameter to be tested. The parameter to be tested is the population proportion Part: 5/6 Part 6 of 6 Determine the test to be performed. We have a simple random sample. The population (Choose one) at least 20 times as large as...

A random sample of 49 measurements from one population had a sample mean of 10, with...

A random sample of 49 measurements from one population had a sample mean of 10, with sample standard deviation 3. An independent random sample of 64 measurements from a second population had a sample mean of 12, with sample standard deviation 4. Test the claim that the population means are different. Use level of significance 0.01. (c) Compute x1 − x2. x1 − x2 = Compute the corresponding sample distribution value. (Test the difference μ1 − μ2. Round your answer...
: In a random sample of 900 teenagers, 148 had used tobacco of some form in...

: In a random sample of 900 teenagers, 148 had used tobacco of some form in the last year. The managers of an anti-tobacco campaign want to claim that less than 20% of all teenagers use tobacco. Test their claim at the 0.01 significance level. (a) What is the sample proportion of teenagers who use tobacco? Round your answer to 3 decimal places. p̂ = (b) What is the test statistic? Round your answer to 2 decimal places. zp hat...
Assume that a simple random sample has been selected from a normally distributed population and test...

Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. A simple random sample of 2525 filtered 100 mm cigarettes is obtained, and the tar content of each cigarette is measured. The sample has a mean of 19.419.4 mg and a standard deviation of 3.553.55 mg. Use a 0.050.05 significance level to...

A random sample of 40 binomial trials resulted in 16 successes. Test the claim that the...

A random sample of 40 binomial trials resulted in 16 successes. Test the claim that the population proportion of successes does not equal 0.50. Use a level of significance of 0.05. Find the P-value of the test statistic. (Round your answer to four decimal places.)
Teenage Tobacco Use: In a random sample of 1100 teenagers, 195 had used tobacco of some...

Teenage Tobacco Use: In a random sample of 1100 teenagers, 195 had used tobacco of some form in the last year. The managers of an anti-tobacco campaign want to claim that less than 20% of all teenagers use tobacco. Test their claim at the 0.05 significance level. (a) What is the sample proportion of teenagers who use tobacco? Round your answer to 3 decimal places. P = (b) What is the test statistic? Round your answer to 2 decimal places....
The number of successes and the sample size for a simple random sample from a population...

The number of successes and the sample size for a simple random sample from a population are given below. X-7, 6-35. H:p=0.4, H:p<0.42-001 a. Determine the sample proportion b. Decide whether using the one-proportion z test is appropriate c. If appropriate, use the one-proportion z test to perform the specified hypothesis test. Click here to view a table of areas under the standard normal curve for negative values of z. c. Determine the test statistic, if appropriate Select the correct...

Assume that a simple random sample has been selected and test the given claim. Identify the null and alternative hypoth...

Assume that a simple random sample has been selected and test the given claim. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Listed below are brain volumes in cm of unrelated subjects used in a study. Use a 0.05 significance level to test the claim that the population of brain volumes has a mean equal to 1099.4 cm. 964 1026 1272 1078 1071 1173 1067 1348 1101 1203 VIAL...

In a simple random sample of 95 families, 70 had one or more pets at home....

Homework Answers