Question

Suppose the following Scheme expression was evaluated. How many times would function foo be called? (let ((cont #f)) (call/cc

0 0
Add a comment Improve this question Transcribed image text
Answer #1

SOLUTION-

Correct answer is "(a) infinity"

Here, foo is the unbound variable. It will run infinite because value of foo is not specified. Hence, it runs continuously.


IF YOU HAVE ANY DOUBT PLEASE COMMENT DOWN BELOW I WILL SOLVE IT FOR YOU:)
----------------PLEASE RATE THE ANSWER-----------THANK YOU!!!!!!!!----------

Add a comment
Know the answer?
Add Answer to:
Suppose the following Scheme expression was evaluated. How many times would function foo be called? (let...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT