Suppose the reaction
A <---> B
in the forward direction is first order in A and the rate constant is 1.50 x 10-2s-1. The reverse reaction is first order in B and the rate constant is 4.50 x 10-2s-1 at the same temperature. What is the value of the equilibrium constant for the reaction
A <---> B
at this temperture?
Chemical equilibrium: In a chemical reaction, when the rate of the forward reaction is equal to the rate of the backward reaction, equilibrium is said to have been attained. The concentration of the reactant and product were maintained in the chemical equilibrium.
Equilibrium constant in terms of : Equilibrium constant is defined as the ratio of the concentration of the product and the concentrations of reactants, raised to their respective stoichiometric powers.
For the gaseous reactant and product the equilibrium can be expressed in terms of partial pressure, Then equilibrium constant will be .
Reaction quotient: Reaction quotient is the ratio of the initial concentrations of reactants to the initial concentrations of products.
Equilibrium constant: Equilibrium constant is the ratio of the rate constant of a forward reaction to the rate constant of a reverse reaction.
The net equilibrium constant of the reaction can be written as
Given chemical reaction:
Given data:
Ans:
Hence, the numerical value of the equilibrium constant for the given equilibrium reaction, at particular temperature is.
Suppose the reaction A <---> B in the forward direction is first order in A and...
Suppose the below reaction in the forward direction is first order in A and the rate constant is 1.30×10-2 s–1. The reverse reaction is first order in B and the rate constant is 4.50×10-2 s–1 at the same temperature. What is the value of the equilibrium constant for the below reaction at this temperature?
01 Question (1 point) Suppose the below reaction in the forward direction is first order in A and the rate constant is 1.10x102 s - A B The reverse reaction is first order in B and the rate constant is 4.50x102s1 at the same temperature. 4th attempt d See Peric What is the value of the equilibrium constant for the below reaction at this temperature? A B 0244 x 10 = K- 0OF 16 QUESTIONS COMPLETED 01/16 VIEW SOLUTION SUB
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Done Edit * Homework segments on S K Day Resources for C ry K Smartwork E c Not secure digital wworton.com/17992 CH14HW 04/24/20 7% 02 Question (1 point) Suppose the below reaction in the forward direction is first order in A and the rate constan AB The reverse reaction is first order in and the tant is 4.70x10's at the same temperature 1st attempt ! See Periodic Table See Hint What is the value of the equilibrium constant for the...
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