A survey reported that 34% of people plan to spend more on eating out after they...
A survey reported that 34% of people plan to spend more on eating out after they retire. If ten people are randomly selected, determine the values below.
|
a. |
The expected number of people who plan to spend more on eating out after they retire |
|
b. |
The standard deviation of the individuals who plan to spend more on eating out after they retire |
|
c. |
The probability that two or fewer in the sample indicate that they actually plan to spend more on eating out after retirement |
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A survey reported that 34% of people plan to spend more on
eating out after they...
An agency collects demographics concerning the number of people in families per household in a certain...
An agency collects demographics concerning the number of people in families per household in a certain country. Assume the distribution of the number of people per household is as shown in the table to the right. a. Calculate the expected number of people in families per household in the country. b. Compute the standard deviation of the number of people in families per household. x P(x) 2 0.25 3 0.24 4 0.31 5 0.12 6 0.05 7 0.03...
A survey asked 11 people to report the amount of money they spend eating out for...
A survey asked 11 people to report the amount of money they spend eating out for lunch on a day. Men Women 19 a) Compare the median amount of money men spend on lunch to that for the women. The median money that men spend was $ and the median for the women was S showing that the typical Select an answer tended to spend more money for lunch. b) Compare the interquartile range for the men to that for...
(5 points, 1 point each) According to survey data by Global Webindex, people spend an average...
(5 points, 1 point each) According to survey data by Global Webindex, people spend an average of 2 hours and 22 minutes (142 minutes) per day on social media. The sample standard deviation given was 43 minutes. Assume this data is normal distributed an answer the following questions. a. What is the probability that a randomly selected person spends more than 2 hours on social media? b. What is the probability that a randomly selected person spends exactly 90 minutes...
A Food Marketing Institute found that 46% of households spend more than $125 a week on...
A Food Marketing Institute found that 46% of households spend more than $125 a week on groceries. Assume the population proportion is 0.46 and a simple random sample of 76 households is selected from the population. What is the probability that the sample proportion of households spending more than S125 a week is more than than 0.38 Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations Answer 1,00000 (Enter your...
A Food Marketing Institute found that 54% of households spend more than $125 a week on...
A Food Marketing Institute found that 54% of households spend more than $125 a week on groceries. Assume the population proportion is 0.54 and a simple random sample of 98 households is selected from the population. hthe ample proportion of households spending more than $125 a weck is more than than 0.4 Note Yousthould caceflly round any z-values you caleulate to 4 decimal places to match wamap's approach and calculations Answer(Enter your answer as a number accurate to 4 decimal...
please kindly make solution and answers visible. thanks The average amount of money that people spend...
please kindly make solution and answers visible. thanks
The average amount of money that people spend at Don Mcalds fast food place is $7.6500 with a standard deviation of $1.8200. 17 customers are randomly selected. Please answer the following questions, and round all answers to 4 decimal places where possible and assume a normal distribution. a. What is the distribution of X? X-NI b. What is the distribution of ? -NE c. What is the distribution of +?\--N d. What...
The average amount of money that people spend at Don Mcalds fast food place is $7.7600 with a standard deviation of $1.5100. 6 customers are randomly selected. Please answer the following questions, a...
The average amount of money that people spend at Don Mcalds fast food place is $7.7600 with a standard deviation of $1.5100. 6 customers are randomly selected. Please answer the following questions, and round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of ¯ x ? ¯ x ~ N= What is the distribution of ∑ x ? ∑ x ~ N= What is the probability that one randomly selected customer...
A Food Marketing Institute found that 34% of households spend more than $125 a week on...
A Food Marketing Institute found that 34% of households spend more than $125 a week on groceries. Assume the population proportion is 0.34 and a simple random sample of 362 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is less than 0.35? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. o.5675* (Enter your answer as...
all answers please 3. The teachers union is concerned about the amount of time teachers spend...
all answers please
3. The teachers union is concerned about the amount of time teachers spend each week doing schoolwork at home. A simple random sample of 56 teachers had a mean of 8.0 hours per week working at home after school. Assume that the population standard deviation is 1.5 hours per week. a) Construct a 95% confidence interval estimate for the mean number of hours per week a teacher spends working at home. b) Does the confidence interval support...
A Food Marketing Institute found that 34% of households spend more than $125 a week on...
A Food Marketing Institute found that 34% of households spend more than $125 a week on groceries. Assume the population proportion is 0.34 and a simple random sample of 147 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.27 and 0.43? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. Do not use tables...
A survey asked 11 people to report the amount of money they spend eating out for lunch on a day. Men Women 19 a) Compare the median amount of money men spend on lunch to that for the women. The median money that men spend was $ and the median for the women was S showing that the typical Select an answer tended to spend more money for lunch. b) Compare the interquartile range for the men to that for...
(5 points, 1 point each) According to survey data by Global Webindex, people spend an average of 2 hours and 22 minutes (142 minutes) per day on social media. The sample standard deviation given was 43 minutes. Assume this data is normal distributed an answer the following questions. a. What is the probability that a randomly selected person spends more than 2 hours on social media? b. What is the probability that a randomly selected person spends exactly 90 minutes...
A Food Marketing Institute found that 46% of households spend more than $125 a week on groceries. Assume the population proportion is 0.46 and a simple random sample of 76 households is selected from the population. What is the probability that the sample proportion of households spending more than S125 a week is more than than 0.38 Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations Answer 1,00000 (Enter your...
A Food Marketing Institute found that 54% of households spend more than $125 a week on groceries. Assume the population proportion is 0.54 and a simple random sample of 98 households is selected from the population. hthe ample proportion of households spending more than $125 a weck is more than than 0.4 Note Yousthould caceflly round any z-values you caleulate to 4 decimal places to match wamap's approach and calculations Answer(Enter your answer as a number accurate to 4 decimal...
please kindly make solution and answers visible. thanks
The average amount of money that people spend at Don Mcalds fast food place is $7.6500 with a standard deviation of $1.8200. 17 customers are randomly selected. Please answer the following questions, and round all answers to 4 decimal places where possible and assume a normal distribution. a. What is the distribution of X? X-NI b. What is the distribution of ? -NE c. What is the distribution of +?\--N d. What...
A Food Marketing Institute found that 34% of households spend more than $125 a week on groceries. Assume the population proportion is 0.34 and a simple random sample of 362 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is less than 0.35? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. o.5675* (Enter your answer as...
all answers please
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